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Time hierarchy (Hartmanis–Stearns 1965): P≠E\mathbf{P} \neq \mathbf{E}P=E

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PvsNP.P_ne_E

by korbonits · Sep 8, 2026 · Mathlib 0df444a (Lean v4.33.1)

complexity-theorymillennium-prizenp-completenessp-vs-nppolynomial-timesatisfiabilityturing-machines

Cook (p. 7–8): "The method of diagonalization with reduction has been used very successfully in computability theory to prove a host of problems undecidable ... It has also been used successfully in complexity theory to prove super-exponential lower bounds for very hard decidable problems." Cook defines (p. 9) "E\mathbf{E}E ... the class of languages recognizable in exponential time; that is the class of languages LLL such that L=L(M)L = L(M)L=L(M) for some Turing machine MMM with TM(n)=O(2cn)T_M(n) = O(2^{cn})TM​(n)=O(2cn) for some c>0c > 0c>0." The separation of polynomial from exponential time is the time hierarchy theorem of Hartmanis and Stearns (1965), the model case of a class separation that diagonalization does prove.

Theorem. P≠E\mathbf{P} \neq \mathbf{E}P=E: the class of languages decidable within a polynomial number of steps is not the class of languages decidable within C⋅2cnC \cdot 2^{cn}C⋅2cn steps for some constants c,Cc, Cc,C. Since every polynomial is eventually below 2n2^n2n, P⊆E\mathbf{P} \subseteq \mathbf{E}P⊆E, so the theorem says that some language is decidable in exponential time but in no polynomial time.

Formalization Note E is defined through Mathlib's Turing.TM2ComputableInTime with the time function bounded by C⋅2cnC \cdot 2^{c n}C⋅2cn for all nnn (equivalent to O(2cn)O(2^{cn})O(2cn), since the bound can absorb finitely many exceptions). A proof requires a coding of multi-stack machines by binary strings, a universal multi-stack machine that simulates a coded machine for a prescribed number of steps with at most exponential overhead, and the diagonal language; none of this exists in Mathlib.

Preamble
import Definitions.Def_PvsNP
import Mathlib
Formal statement
namespace PvsNP
theorem P_ne_E : P ≠ E := by sorry
end PvsNP
Source
S. Cook, The P versus NP problem, Clay Mathematics Institute Millennium Prize Problem description (2000), https://www.claymath.org/wp-content/uploads/2022/06/pvsnp.pdf, p. 7–8 (diagonalization with reduction) and p. 9 (definition of the class E). Original: J. Hartmanis and R. E. Stearns, On the computational complexity of algorithms, Trans. Amer. Math. Soc. 117 (1965), 285–306, https://doi.org/10.1090/S0002-9947-1965-0170805-7
Read-back

What the Lean code literally says, in plain math · claude-fable-5-1

Read-back: PvsNP.P_ne_E

The statement. The theorem asserts that two specific sets of languages over the two-letter alphabet {true,false}\{\mathsf{true},\mathsf{false}\}{true,false}, called P\mathbf{P}P and E\mathbf{E}E below, are not equal as sets:

P≠E.\mathbf{P} \neq \mathbf{E}.P=E.

Here a string is a finite list www of Booleans (the empty string included), a language LLL is an arbitrary set of such strings, and P\mathbf{P}P and E\mathbf{E}E are sets of languages. The statement is only the negation of set equality: it says it is not the case that every language in P\mathbf{P}P lies in E\mathbf{E}E and every language in E\mathbf{E}E lies in P\mathbf{P}P. Classically this is equivalent to: there is a language L⊆{true,false}∗L \subseteq \{\mathsf{true},\mathsf{false}\}^{*}L⊆{true,false}∗ lying in exactly one of P\mathbf{P}P, E\mathbf{E}E. The statement does not say which of the two sets contains such an LLL, does not assert P⊆E\mathbf{P} \subseteq \mathbf{E}P⊆E, and does not assert that either set is a proper subset of the other. There are no hypotheses, free variables, or typeclass assumptions: it is a closed proposition. Both P\mathbf{P}P and E\mathbf{E}E are custom definitions from the preamble, unfolded in full below; everything hinges on a particular stack-machine model (also unfolded).


The machine model (used by both sets). A bundled stack machine M\mathcal{M}M consists of:

  • a finite index set KKK of stacks (with decidable equality), together with two distinguished indices k0k_0k0​ (input stack) and k1k_1k1​ (output stack), which are not required to be distinct;
  • for each stack index k∈Kk \in Kk∈K a type Γk\Gamma_kΓk​ of stack symbols; only Γk0\Gamma_{k_0}Γk0​​ is required to be finite (but see the alphabet conditions below, which force Γk0\Gamma_{k_0}Γk0​​ and Γk1\Gamma_{k_1}Γk1​​ to be two-element types); the symbol types of any other stacks are arbitrary types, not required to be finite;
  • a finite type Λ\LambdaΛ of program labels with a distinguished label main\mathrm{main}main;
  • a finite type σ\sigmaσ of internal states with a distinguished initial state s0s_0s0​;
  • a program m:Λ→Stmtm : \Lambda \to \mathrm{Stmt}m:Λ→Stmt, assigning to each label a statement. A statement is a finite tree built from: pushk(f,q)\mathrm{push}_k(f, q)pushk​(f,q) with f:σ→Γkf : \sigma \to \Gamma_kf:σ→Γk​ (push f(v)f(v)f(v) on stack kkk, continue with qqq); peekk(f,q)\mathrm{peek}_k(f, q)peekk​(f,q) with f:σ→Option(Γk)→σf : \sigma \to \mathrm{Option}(\Gamma_k) \to \sigmaf:σ→Option(Γk​)→σ (update the state from the top of stack kkk, if any, without removing it); popk(f,q)\mathrm{pop}_k(f, q)popk​(f,q) (same, but remove the top element if present; popping an empty stack leaves it empty); load(a,q)\mathrm{load}(a, q)load(a,q) with a:σ→σa : \sigma \to \sigmaa:σ→σ; branch(b,q1,q2)\mathrm{branch}(b, q_1, q_2)branch(b,q1​,q2​) with b:σ→Boolb : \sigma \to \mathrm{Bool}b:σ→Bool; goto(ℓ)\mathrm{goto}(\ell)goto(ℓ) with ℓ:σ→Λ\ell : \sigma \to \Lambdaℓ:σ→Λ; and halt\mathrm{halt}halt. The functions f,a,b,ℓf, a, b, \ellf,a,b,ℓ appearing in statements are arbitrary set-theoretic functions (no computability requirement on them; their domains σ\sigmaσ are finite).

A configuration is a triple (ℓ,v,S)(\ell, v, S)(ℓ,v,S): a current label ℓ∈Option(Λ)\ell \in \mathrm{Option}(\Lambda)ℓ∈Option(Λ) (with ℓ=none\ell = \mathrm{none}ℓ=none meaning "halted"), an internal state v∈σv \in \sigmav∈σ, and a family S=(Sk)k∈KS = (S_k)_{k\in K}S=(Sk​)k∈K​ of stacks, each a finite list over Γk\Gamma_kΓk​. One step of M\mathcal{M}M from (some ℓ,v,S)(\mathrm{some}\ \ell, v, S)(some ℓ,v,S) executes the entire statement m(ℓ)m(\ell)m(ℓ) — all of its pushes/peeks/pops/loads/branches, however many — until it reaches a goto(ℓ′)\mathrm{goto}(\ell')goto(ℓ′) (giving the new configuration (some ℓ′(v′),v′,S′)(\mathrm{some}\ \ell'(v'), v', S')(some ℓ′(v′),v′,S′)) or a halt\mathrm{halt}halt (giving (none,v′,S′)(\mathrm{none}, v', S')(none,v′,S′)). A step from a configuration with label none\mathrm{none}none is undefined (the computation is over). Time is measured as the number of such steps; a single step may perform an unbounded-in-principle but program-fixed finite number of stack operations.

The initial configuration for an input list uuu over Γk0\Gamma_{k_0}Γk0​​ is (some main, s0, S)(\mathrm{some}\ \mathrm{main},\ s_0,\ S)(some main, s0​, S) with Sk0=uS_{k_0} = uSk0​​=u (first symbol of uuu on top) and Sk=[ ]S_k = [\,]Sk​=[] for every other kkk. The halting configuration for an output list u′u'u′ over Γk1\Gamma_{k_1}Γk1​​ is (none, s0, S′)(\mathrm{none},\ s_0,\ S')(none, s0​, S′) with Sk1′=u′S'_{k_1} = u'Sk1​′​=u′ and Sk′=[ ]S'_k = [\,]Sk′​=[] for every k≠k1k \neq k_1k=k1​. Note that the halting configuration requires the internal state to be exactly the initial state s0s_0s0​ again, and every stack other than the output stack to be exactly empty.

"M\mathcal{M}M outputs u′u'u′ on input uuu within ttt steps" means: there is a natural number s≤ts \le ts≤t such that after exactly sss steps from the initial configuration for uuu the configuration is exactly the halting configuration for u′u'u′ (formally, the sss-fold iterate of the step function, extended to Option\mathrm{Option}Option so that an undefined step stays undefined, applied to the initial configuration equals some\mathrm{some}some of the halting configuration). Because a halted configuration has no successor, this forces every intermediate configuration to be non-halted, and the machine to halt precisely at step sss.


Deciders. Let χ:{true,false}∗→{true,false}\chi : \{\mathsf{true},\mathsf{false}\}^{*} \to \{\mathsf{true},\mathsf{false}\}χ:{true,false}∗→{true,false} be a total function on strings. A machine computing χ\chiχ with time function TTT (this is the Mathlib notion TM2ComputableInTime with input encoding the identity on strings and output encoding b↦[b]b \mapsto [b]b↦[b]) is a bundled stack machine M\mathcal{M}M together with

  • a bijection ι0:Γk0≃Bool\iota_0 : \Gamma_{k_0} \simeq \mathrm{Bool}ι0​:Γk0​​≃Bool (input alphabet) and a bijection ι1:Γk1≃Bool\iota_1 : \Gamma_{k_1} \simeq \mathrm{Bool}ι1​:Γk1​​≃Bool (output alphabet), so both Γk0\Gamma_{k_0}Γk0​​ and Γk1\Gamma_{k_1}Γk1​​ are two-element types;
  • a time function T:N→NT : \mathbb{N} \to \mathbb{N}T:N→N (the structure's time field), an arbitrary function of the input length;
  • for every string www (including the empty string, of length 000), a witness that M\mathcal{M}M outputs the one-element list [ι1−1(χ(w))][\iota_1^{-1}(\chi(w))][ι1−1​(χ(w))] on input ι0−1(w)\iota_0^{-1}(w)ι0−1​(w) (the string www transported symbol-wise onto the input alphabet) within T(∣w∣)T(|w|)T(∣w∣) steps, in the exact sense defined above (halting with state s0s_0s0​, output stack holding exactly one symbol, all other stacks empty).

A polynomial-time machine computing χ\chiχ (TM2ComputableInPolyTime, same encodings) is the same, except that the time field is a polynomial p∈N[X]p \in \mathbb{N}[X]p∈N[X] with natural-number coefficients, and the step bound for input www is p(∣w∣)p(|w|)p(∣w∣).


The set P\mathbf{P}P. A language LLL belongs to P\mathbf{P}P if and only if there exists a total function χ:{true,false}∗→Bool\chi : \{\mathsf{true},\mathsf{false}\}^{*} \to \mathrm{Bool}χ:{true,false}∗→Bool such that

  1. there exists (as a mere existence statement, Nonempty) a polynomial-time machine computing χ\chiχ in the sense just defined, and
  2. for every string www:   w∈L  ⟺  χ(w)=true\; w \in L \iff \chi(w) = \mathsf{true}w∈L⟺χ(w)=true.

Condition 2 means LLL is exactly χ−1(true)\chi^{-1}(\mathsf{true})χ−1(true); in particular LLL is determined by χ\chiχ, and the empty language and the language of all strings are obtained from constant χ\chiχ.

The set E\mathbf{E}E. A language LLL belongs to E\mathbf{E}E if and only if there exists a total function χ:{true,false}∗→Bool\chi : \{\mathsf{true},\mathsf{false}\}^{*} \to \mathrm{Bool}χ:{true,false}∗→Bool such that

  1. there exists a machine M\mathcal{M}M computing χ\chiχ with some time function T:N→NT : \mathbb{N}\to\mathbb{N}T:N→N (the TM2ComputableInTime structure above), together with natural numbers c,C∈Nc, C \in \mathbb{N}c,C∈N such that
∀n∈N,T(n)  ≤  C⋅2 c n,\forall n \in \mathbb{N},\qquad T(n) \;\le\; C \cdot 2^{\,c\,n},∀n∈N,T(n)≤C⋅2cn,

and 2. for every string www:   w∈L  ⟺  χ(w)=true\; w \in L \iff \chi(w) = \mathsf{true}w∈L⟺χ(w)=true.

In item 1 the bound is on the machine's declared time function TTT itself (for all nnn, including n=0n=0n=0 and lengths of no particular interest), not directly on the actual step counts; the actual step count on input www is separately required to be ≤T(∣w∣)\le T(|w|)≤T(∣w∣). The parameters ccc and CCC range over all natural numbers: c=0c = 0c=0 is allowed (giving a constant bound T(n)≤CT(n) \le CT(n)≤C), and C=0C = 0C=0 is allowed (giving T≡0T \equiv 0T≡0, which would require halting in 000 steps; since the initial configuration is never a halting configuration, no machine satisfies this, so that case contributes nothing). No monotonicity or other regularity of TTT is required.


Summary of what is asserted. With P\mathbf{P}P = "languages χ−1(true)\chi^{-1}(\mathsf{true})χ−1(true) for some χ\chiχ admitting a bundled stack machine, of the exact form above, whose step count on every input www is at most p(∣w∣)p(|w|)p(∣w∣) for a polynomial p∈N[X]p \in \mathbb{N}[X]p∈N[X]" and E\mathbf{E}E = "languages χ−1(true)\chi^{-1}(\mathsf{true})χ−1(true) for some χ\chiχ admitting such a machine whose declared time function TTT satisfies T(n)≤C⋅2cnT(n) \le C\cdot 2^{cn}T(n)≤C⋅2cn for all nnn, for some c,C∈Nc, C \in \mathbb{N}c,C∈N", the theorem states precisely that these two sets of languages over {true,false}\{\mathsf{true},\mathsf{false}\}{true,false} are distinct.

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