Trautman is a closed spatial Hessian
OpenNewtonCartan.riem00_is_closed_FAssume a classical connection satisfies CurvConds for smooth and that its Riemann tensor has already been reduced to the Trautman form
Then the field is smooth and satisfies
together with the trace identity coming from CurvConds (1).
These are precisely the hypotheses of the Poincaré lemma that produces the recovering potential. Symmetry of is CurvConds (2) on the indices ; vanishing of temporal components uses and antisymmetry of Riemann; closedness of the spatial Hessian follows from the Bianchi identity / equality of mixed partials of the Christoffel symbols under ContDiff; the trace is Ricci.
Formalization Note. Uses riem, CurvConds, and pd from Def_NewtonCartan_defs.
DEPRECATED: the universal closed-Hessian condition ∀ i j k, ∂_k F^i_j = ∂_j F^i_k (including temporal indices) is false for Trautman F. Counterexample: Γ^i_00 = x^i f(t) gives F^i_j = δ^i_j f(t) with ∂_0 F ≠ 0 while F^i_0 = 0. Replaced by NewtonCartan.riem00_spatial_closed_F (spatial indices only).
import Definitions.Def_NewtonCartan_defs open scoped ContDiff
namespace NewtonCartan
/-- Under CurvConds and the Trautman $t_b$-form, $F^a{}_d := R^a{}_{00d}$ is smooth, vanishes on temporal indices, is symmetric, and is closed as a spatial Hessian; its trace is $4\pi\rho$. -/
theorem riem00_is_closed_F (Γt : Conn) (ρ : E → ℝ)
(hΓt : IsClassical Γt) (hρ : ContDiff ℝ ∞ ρ) (hcurv : CurvConds Γt ρ)
(hform : ∀ x a b c d,
riem Γt x a b c d =
tt b * (tt c * riem Γt x a 0 0 d - tt d * riem Γt x a 0 0 c)) :
let F : E → Fin 4 → Fin 4 → ℝ := fun x a d => riem Γt x a 0 0 d
ContDiff ℝ ∞ F ∧
(∀ x d, F x 0 d = 0) ∧ (∀ x a, F x a 0 = 0) ∧
(∀ x i j, F x i j = F x j i) ∧
(∀ x i j k, pd (fun y => F y i j) k x = pd (fun y => F y i k) j x) ∧
(∀ x, ∑ i : Fin 4, F x i i = 4 * Real.pi * ρ x) := by sorry
end NewtonCartan