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Three attained SDP characterizations of W

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QAlgorithms.Papers.Independent.Intakethird100.P83.sdpDuality

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let ρ\rhoρ be any normalized bipartite state on nonzero finite-dimensional spaces, and let TBT_BTB​ denote ordinary partial transpose on Bob. All operator inequalities are Loewner inequalities, ∥⋅∥∞\|\cdot\|_\infty∥⋅∥∞​ is the largest singular value, and ∥⋅∥1\|\cdot\|_1∥⋅∥1​ is the trace norm. The following three optimization problems have the same value and each attains its optimum:

W(ρ)=max⁡R=R†{Re⁡Tr⁡(TB(ρ)R):∥R∥∞≤1, TB(R)≥0}=min⁡U,V≥0{Re⁡Tr⁡(U+V):TB(U−V)≥ρ}=min⁡X≥ρ∥TB(X)∥1.\begin{aligned}W(\rho)&=\max_{R=R^\dagger}\{\operatorname{Re}\operatorname{Tr}(T_B(\rho)R):\|R\|_\infty\le1,\ T_B(R)\ge0\}\\&=\min_{U,V\ge0}\{\operatorname{Re}\operatorname{Tr}(U+V):T_B(U-V)\ge\rho\}\\&=\min_{X\ge\rho}\|T_B(X)\|_1.\end{aligned}W(ρ)​=R=R†max​{ReTr(TB​(ρ)R):∥R∥∞​≤1, TB​(R)≥0}=U,V≥0min​{ReTr(U+V):TB​(U−V)≥ρ}=X≥ρmin​∥TB​(X)∥1​.​

These are explicit finite-dimensional SDPs. The first witness need not be positive, and the last variable is not constrained to have trace one.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P83
Formal statement
noncomputable section

open scoped Matrix ComplexConjugate ComplexOrder

open Filter

namespace QAlgorithms.Papers.Independent.Intakethird100.P83

open QAlgorithms.Papers.Independent.Support50.P11 (Loewner)

open QAlgorithms.Papers.Independent.Dependency50.P32 (partialTranspose)

open QAlgorithms.Papers.Independent.Information100.P34 (supportProjector)

variable {A B C D : Type*}

variable [Fintype A] [Fintype B] [Fintype C] [Fintype D]

variable [DecidableEq A] [DecidableEq B] [DecidableEq C] [DecidableEq D]

/-- Strong duality and attained equivalent SDPs (7)–(9), PDF p.2.
R need not be positive and X need not have trace one. -/
theorem sdpDuality [Nonempty A] [Nonempty B]
    (rho : Matrix (A × B) (A × B) ℂ) (hrho : IsDensityMatrix rho) :
    wValue rho = dualUVValue rho ∧ wValue rho = dualXValue rho ∧
    (∃ R, WFeasible R ∧ effectProb (partialTranspose rho) R = wValue rho) ∧
    (∃ U V, DualUVFeasible rho U V ∧ (U + V).trace.re = dualUVValue rho) ∧
    (∃ X, Loewner rho X ∧ traceNorm (partialTranspose X) = dualXValue rho) := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P83

end
Source
Improved Semidefinite Programming Upper Bound on Distillable Entanglement, arXiv:1601.07940v4, PDF p. 2, Unnumbered result: equivalent attained SDPs (7)–(9)
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What the Lean code literally says, in plain math · gpt-6.1-sol

Let A,BA,BA,B be finite nonempty types with decidable equality, and let ρ\rhoρ be a positive semidefinite complex matrix indexed by A×BA\times BA×B, with trace 111. Write X(a,b),(a′,b′)Γ=X(a,b′),(a′,b)X^\Gamma_{(a,b),(a',b')}=X_{(a,b'),(a',b)}X(a,b),(a′,b′)Γ​=X(a,b′),(a′,b)​, X≤YX\le YX≤Y for positive semidefiniteness of Y−XY-XY−X, ∥X∥op\|X\|_{\mathrm{op}}∥X∥op​ for the Euclidean operator norm, and ∥X∥1=Re⁡tr⁡X†X\|X\|_1=\operatorname{Re}\operatorname{tr}\sqrt{X^\dagger X}∥X∥1​=RetrX†X​. Define the following real optimization values:

w(ρ)=sup⁡{Re⁡tr⁡(ρΓR):R=R†, ∥R∥op≤1, RΓ≥0},dUV(ρ)=inf⁡{Re⁡tr⁡(U+V):U≥0, V≥0, ρ≤(U−V)Γ},dX(ρ)=inf⁡{∥XΓ∥1:ρ≤X}.\begin{aligned} w(\rho)&=\sup\{\operatorname{Re}\operatorname{tr}(\rho^\Gamma R): R=R^\dagger,\ \|R\|_{\mathrm{op}}\le1,\ R^\Gamma\ge0\},\\ d_{UV}(\rho)&=\inf\{\operatorname{Re}\operatorname{tr}(U+V): U\ge0,\ V\ge0,\ \rho\le(U-V)^\Gamma\},\\ d_X(\rho)&=\inf\{\|X^\Gamma\|_1:\rho\le X\}. \end{aligned}w(ρ)dUV​(ρ)dX​(ρ)​=sup{Retr(ρΓR):R=R†, ∥R∥op​≤1, RΓ≥0},=inf{Retr(U+V):U≥0, V≥0, ρ≤(U−V)Γ},=inf{∥XΓ∥1​:ρ≤X}.​

All optimization matrices have the same indices as ρ\rhoρ. The theorem asserts w(ρ)=dUV(ρ)=dX(ρ)w(\rho)=d_{UV}(\rho)=d_X(\rho)w(ρ)=dUV​(ρ)=dX​(ρ), and asserts attainment in all three problems: there exists a feasible RRR with Re⁡tr⁡(ρΓR)=w(ρ)\operatorname{Re}\operatorname{tr}(\rho^\Gamma R)=w(\rho)Retr(ρΓR)=w(ρ), there exist feasible U,VU,VU,V with Re⁡tr⁡(U+V)=dUV(ρ)\operatorname{Re}\operatorname{tr}(U+V)=d_{UV}(\rho)Retr(U+V)=dUV​(ρ), and there exists XXX with X−ρ≥0X-\rho\ge0X−ρ≥0 and ∥XΓ∥1=dX(ρ)\|X^\Gamma\|_1=d_X(\rho)∥XΓ∥1​=dX​(ρ).

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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