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Proposition 2.4: sufficiency of the zero-marginal perturbation criterion

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QAlgorithms.Papers.Independent.Intakethird100.P12.zero_marginal_sufficiency

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let d1,d2d_1,d_2d1​,d2​ be the dimensions of finite-dimensional complex Hilbert spaces with chosen orthonormal bases. Let ρ1,ρ2\rho_1,\rho_2ρ1​,ρ2​ be positive semidefinite operators of trace one. Write C(ρ1,ρ2)C(\rho_1,\rho_2)C(ρ1​,ρ2​) for all joint density matrices with these two partial traces, and E(ρ1,ρ2)E(\rho_1,\rho_2)E(ρ1​,ρ2​) for its extreme points over the real scalars. Coordinates in the tensor product use lexicographic order.

Let ρ∈C(ρ1,ρ2)\rho\in C(\rho_1,\rho_2)ρ∈C(ρ1​,ρ2​) have rank k<nk<nk<n.

Set n=d1d2n=d_1d_2n=d1​d2​ and k=rank⁡ρk=\operatorname{rank}\rhok=rankρ. Let σ\sigmaσ be a permutation unitary, AAA a complex k×(n−k)k\times(n-k)k×(n−k) matrix, and KKK a strictly positive definite k×kk\times kk×k matrix satisfying

σρσ−1=BA(K),BA(L)=(LLAA†LA†LA).\sigma\rho\sigma^{-1}=B_A(K),\qquad B_A(L)=\begin{pmatrix}L&LA\\A^\dagger L&A^\dagger LA\end{pmatrix}.σρσ−1=BA​(K),BA​(L)=(LA†L​LAA†LA​).

Here †\dagger† denotes conjugate transpose. Both marginals of σ−1BA(L)σ\sigma^{-1}B_A(L)\sigmaσ−1BA​(L)σ are computed in the original tensor coordinates.

Suppose that every Hermitian matrix LLL of order kkk satisfies

[Tr⁡H2(σ−1BA(L)σ)=0 and Tr⁡H1(σ−1BA(L)σ)=0] ⟹ L=0.\bigl[\operatorname{Tr}_{H_2}(\sigma^{-1}B_A(L)\sigma)=0\ \text{and}\ \operatorname{Tr}_{H_1}(\sigma^{-1}B_A(L)\sigma)=0\bigr]\ \Longrightarrow\ L=0.[TrH2​​(σ−1BA​(L)σ)=0 and TrH1​​(σ−1BA​(L)σ)=0] ⟹ L=0.

Then

ρ∈E(ρ1,ρ2).\rho\in E(\rho_1,\rho_2).ρ∈E(ρ1​,ρ2​).

This supplies the converse to the necessary perturbation condition, without assuming any factorization of midpoint summands.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P12
Formal statement
namespace QAlgorithms.Papers.Independent.Intakethird100.P12

open scoped ComplexConjugate ComplexOrder

/-- Proposition 2.4, PDF p.7: injectivity is a hypothesis, extremality the conclusion.
No midpoint factorization is imposed as an additional hypothesis. -/
theorem zero_marginal_sufficiency {d1 d2 k : ℕ}
    (rho1 : Matrix (Fin d1) (Fin d1) ℂ) (rho2 : Matrix (Fin d2) (Fin d2) ℂ)
    (hm1 : IsDensityMatrix rho1) (hm2 : IsDensityMatrix rho2)
    (rho : Matrix (Fin d1 × Fin d2) (Fin d1 × Fin d2) ℂ)
    (hmem : rho ∈ finiteCouplingSet rho1 rho2) (hrank : rho.rank = k)
    (hkn : k < d1*d2) (p : Equiv.Perm (Fin (d1*d2)))
    (A : Matrix (Fin k) (Fin (d1*d2-k)) ℂ) (K : Matrix (Fin k) (Fin k) ℂ)
    (hK : K.PosDef) (hblock : permuteMatrix p (flatMatrix rho) = rankBlockMatrix hkn.le K A)
    (hinjective : NoZeroMarginalPerturbation hkn.le p A) :
    rho ∈ Set.extremePoints ℝ (finiteCouplingSet rho1 rho2) := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P12
Source
Extremal Quantum States in Coupled Systems, arXiv:quant-ph/0307182v1, PDF p. 7, Proposition 2.4: sufficiency of the zero-marginal perturbation criterion
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What the Lean code literally says, in plain math · gpt-6.1-sol

For any natural numbers d1,d2,kd_1,d_2,kd1​,d2​,k, let ρ1,ρ2\rho_1,\rho_2ρ1​,ρ2​ be complex positive semidefinite matrices of sizes d1,d2d_1,d_2d1​,d2​, each with trace 111, and let CCC consist of all positive semidefinite matrices σ\sigmaσ of trace 111 on the product index set whose two partial traces are ρ1,ρ2\rho_1,\rho_2ρ1​,ρ2​; explicitly, these partial traces have entries ∑jσ(i,j),(i′,j)\sum_j\sigma_{(i,j),(i',j)}∑j​σ(i,j),(i′,j)​ and ∑iσ(i,j),(i,j′)\sum_i\sigma_{(i,j),(i,j')}∑i​σ(i,j),(i,j′)​, respectively. Suppose ρ∈C\rho\in Cρ∈C, rank⁡C(ρ)=k\operatorname{rank}_{\mathbb C}(\rho)=krankC​(ρ)=k, and k<n:=d1d2k<n:=d_1d_2k<n:=d1​d2​. Write β(i,j)=id2+j\beta(i,j)=id_2+jβ(i,j)=id2​+j, and flatten a product-indexed matrix by F(σ)u,v=σβ−1(u),β−1(v)F(\sigma)_{u,v}=\sigma_{\beta^{-1}(u),\beta^{-1}(v)}F(σ)u,v​=σβ−1(u),β−1(v)​. For every permutation ppp of {0,…,n−1}\{0,\ldots,n-1\}{0,…,n−1}, every complex k×(n−k)k\times(n-k)k×(n−k) matrix AAA, and every positive definite complex k×kk\times kk×k matrix KKK, assume

F(ρ)p(u),p(v)=(KKAA∗KA∗KA)u,v,F(\rho)_{p(u),p(v)} = \begin{pmatrix} K&KA\\ A^*K&A^*KA \end{pmatrix}_{u,v},F(ρ)p(u),p(v)​=(KA∗K​KAA∗KA​)u,v​,

where the blocks use the first kkk and last n−kn-kn−k coordinates and ∗^{*}∗ denotes conjugate transpose. For each complex k×kk\times kk×k matrix LLL, define a product-indexed matrix ΔL\Delta_LΔL​ by

(ΔL)a,b=(LLAA∗LA∗LA)p−1(β(a)), p−1(β(b)).(\Delta_L)_{a,b} = \begin{pmatrix} L&LA\\ A^*L&A^*LA \end{pmatrix}_{p^{-1}(\beta(a)),\,p^{-1}(\beta(b))}.(ΔL​)a,b​=(LA∗L​LAA∗LA​)p−1(β(a)),p−1(β(b))​.

Assume that every Hermitian LLL for which both partial traces vanish,

∑j(ΔL)(i,j),(i′,j)=0for all i,i′,∑i(ΔL)(i,j),(i,j′)=0for all j,j′,\sum_j(\Delta_L)_{(i,j),(i',j)}=0\quad\text{for all }i,i', \qquad \sum_i(\Delta_L)_{(i,j),(i,j')}=0\quad\text{for all }j,j',j∑​(ΔL​)(i,j),(i′,j)​=0for all i,i′,i∑​(ΔL​)(i,j),(i,j′)​=0for all j,j′,

equals zero. Then ρ\rhoρ is an extreme point of CCC over the real numbers. The hypotheses exclude full rank; they also rule out k=0k=0k=0 and zero marginal dimensions because ρ,ρ1,ρ2\rho,\rho_1,\rho_2ρ,ρ1​,ρ2​ have trace 111.

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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