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Theorem 6.1 — counterexample to the complete bunkbed conjecture

Proved
BunkbedFalse.complete_counterexample

by burkh4rt · Oct 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricsgraph-theorypercolationprobability

There exists a finite connected simple graph G=(V,E)G=(V,E)G=(V,E) with

∣V∣<106,∣E∣<106,|V|<10^6,\qquad |E|<10^6,∣V∣<106,∣E∣<106,

and vertices u,v∈Vu,v\in Vu,v∈V such that independent bond percolation with retention probability 1/21/21/2 on the Cartesian product G×K2G\times K_2G×K2​ satisfies

P1/2(u0↔v0)<P1/2(u0↔v1).\mathbb P_{1/2}(u_0\leftrightarrow v_0)<\mathbb P_{1/2}(u_0\leftrightarrow v_1).P1/2​(u0​↔v0​)<P1/2​(u0​↔v1​).

Every horizontal edge and every vertical edge is independently retained with probability 1/21/21/2. In particular, the complete bunkbed conjecture is false.

Formalization Note. The vertex set is represented by {0,…,n−1}\{0,\ldots,n-1\}{0,…,n−1}, and the edge bound counts the edges of the resulting simple graph. The connection probabilities are exact finite rational sums.

Preamble
import Definitions.Def_BunkbedComplete
open Bunkbed Finset SimpleGraph
Formal statement
theorem BunkbedFalse.complete_counterexample :
    ∃ (n : ℕ) (E : Finset (Sym2 (Fin n))) (u v : Fin n),
      n < 1000000 ∧ (ofEdges E).edgeFinset.card < 1000000 ∧
      (ofEdges E).Connected ∧
      completeProb E (1 / 2) (u, 0) (v, 0) <
        completeProb E (1 / 2) (u, 0) (v, 1) := by sorry
Source
N. Gladkov, I. Pak, A. Zimin, The bunkbed conjecture is false, PNAS 122 (2025), e2420725122, https://www.math.ucla.edu/~pak/papers/Bunkbed-PNAS.pdf#page=9, Section 6, Theorem 6.1.

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