Theorem 6.1 — counterexample to the complete bunkbed conjecture
ProvedBunkbedFalse.complete_counterexamplecombinatoricsgraph-theorypercolationprobability
There exists a finite connected simple graph with
and vertices such that independent bond percolation with retention probability on the Cartesian product satisfies
Every horizontal edge and every vertical edge is independently retained with probability . In particular, the complete bunkbed conjecture is false.
Formalization Note. The vertex set is represented by , and the edge bound counts the edges of the resulting simple graph. The connection probabilities are exact finite rational sums.
Preamble
import Definitions.Def_BunkbedComplete open Bunkbed Finset SimpleGraph
Formal statement
theorem BunkbedFalse.complete_counterexample :
∃ (n : ℕ) (E : Finset (Sym2 (Fin n))) (u v : Fin n),
n < 1000000 ∧ (ofEdges E).edgeFinset.card < 1000000 ∧
(ofEdges E).Connected ∧
completeProb E (1 / 2) (u, 0) (v, 0) <
completeProb E (1 / 2) (u, 0) (v, 1) := by sorrySource
N. Gladkov, I. Pak, A. Zimin, The bunkbed conjecture is false, PNAS 122 (2025), e2420725122, https://www.math.ucla.edu/~pak/papers/Bunkbed-PNAS.pdf#page=9, Section 6, Theorem 6.1.