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lean_workbook_plus_63317

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Originally, each person had to pay \\frac{900}{x}(xisthenumberofpeople).Then,fivepeopleleft,soeachpersonthenhadtopay(x is the number of people). Then, five people left, so each person then had to pay(xisthenumberofpeople).Then,fivepeopleleft,soeachpersonthenhadtopay$\frac{900}{x-5}.Wearegiventhat. We are given that.Wearegiventhat$\frac{900}{x-5}is2.5greaterthanis 2.5 greater thanis2.5greaterthan$\frac{900}{x}.So,. So,.So,\frac{900}{x}=\frac{900}{x-5}-2.5.Solving,weget. Solving, we get.Solving,wegetx=-40,45,butwewantthepositive,so, but we want the positive, so,butwewantthepositive,sox=45.Sincewewantthenumberofpeople,and. Since we want the number of people, and.Sincewewantthenumberofpeople,andxisthenumberofpeople,wefindthatthenumberofpeoplethathadtosharethepricewasis the number of people, we find that the number of people that had to share the price wasisthenumberofpeople,wefindthatthenumberofpeoplethathadtosharethepricewas\boxed{45}$

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem lean_workbook_plus_63317  (x : ℝ)
  (h₀ : 0 < x)
  (h₁ : 900 / (x - 5) = 900 / x + 2.5) :
  x = 45   :=  by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook

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