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Linear_Combination_of_Convergent_Series

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

proofwikiseries

Let \sequenceann≥1\sequence {a_n}_{n \mathop \ge 1}\sequencean​n≥1​ and \sequencebnn≥1\sequence {b_n}_{n \mathop \ge 1}\sequencebn​n≥1​ be sequences of real numbers. Let the two series ∑n=1∞an\displaystyle \sum_{n \mathop = 1}^\infty a_nn=1∑∞​an​ and ∑n=1∞bn\displaystyle \sum_{n \mathop = 1}^\infty b_nn=1∑∞​bn​ converge to α\alphaα and β\betaβ respectively. Let λ,μ∈R\lambda, \mu \in \Rλ,μ∈R be real numbers. Then the series ∑n=1∞\parenλan+μbn\displaystyle \sum_{n \mathop = 1}^\infty \paren {\lambda a_n + \mu b_n}n=1∑∞​\parenλan​+μbn​ converges to λα+μβ\lambda \alpha + \mu \betaλα+μβ.

Preamble
import Mathlib.Analysis.Complex.Basic
import Mathlib.Topology.Algebra.InfiniteSum.Basic
Formal statement
import Mathlib.Analysis.Complex.Basic
import Mathlib.Topology.Algebra.InfiniteSum.Basic

theorem Linear_Combination_of_Convergent_Series (a b : ℕ → ℝ) (ha : Summable a) (hb : Summable b) (c d : ℝ) : Summable (fun n => c * a n + d * b n) ∧ ∑' n, (c * a n + d * b n) = c * ∑' n, a n + d * ∑' n, b n := by sorry
Source
https://proofwiki.org/wiki/Linear_Combination_of_Convergent_Series

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