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Equation (6): the marginal is a positive probability density

Proved
FlowMatchingT1.marginal_probability

by MiltMont · Sep 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

analysiscontinuity-equationflow-matchingmeasure-theory

Let ddd be any natural number, E=RdE=\mathbb R^dE=Rd, and QQQ a Borel probability measure on EEE. Suppose that for every t∈[0,1]t\in[0,1]t∈[0,1], the real function ρ(t,x,z)\rho(t,x,z)ρ(t,x,z) is jointly measurable in (x,z)(x,z)(x,z) and strictly positive at every pair (x,z)(x,z)(x,z); for each zzz, its integral in xxx is one and it is Lebesgue integrable; and for each xxx, its integral in zzz against QQQ is integrable. Then the mixture p(t,x)=∫ρ(t,x,z) dQ(z)p(t,x)=\int\rho(t,x,z)\,dQ(z)p(t,x)=∫ρ(t,x,z)dQ(z) satisfies

p(t,x)>0for all x,∫Ep(t,x) dx=1,p(t,x)>0\quad\text{for all }x,\qquad \int_Ep(t,x)\,dx=1,p(t,x)>0for all x,∫E​p(t,x)dx=1,

and is Lebesgue integrable, for every t∈[0,1]t\in[0,1]t∈[0,1]. This establishes the probability-path meaning of equation (6), including positivity needed by the velocity formula. It requires no velocity field or derivative assumptions.

Preamble
import Definitions.Def_FlowMatchingT1
open MeasureTheory
open FlowMatchingT1

Formal statement
theorem FlowMatchingT1.marginal_probability
    {d : ℕ} (Q : Measure (Space d)) [IsProbabilityMeasure Q]
    (ρ : ℝ → Space d → Space d → ℝ) (hρ : DensityHypotheses Q ρ) :
    ∀ t ∈ Set.Icc (0 : ℝ) 1,
      ProbabilityDensity (marginalDensity Q ρ t) ∧
      ∀ x, 0 < marginalDensity Q ρ t x := by sorry
Source
Y. Lipman, R. T. Q. Chen, H. Ben-Hamu, M. Nickel, M. Le, Flow Matching for Generative Modeling, ICLR 2023; https://arxiv.org/abs/2210.02747v2; Section 2, Section 3.1, Theorem 1, equations (6), (8), (26), Appendix A proof of Theorem 1.
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What the Lean code literally says, in plain math · gpt-6-astra

For every natural number ddd (including d=0d=0d=0), let X=RdX=\mathbb R^dX=Rd, represented as the real-valued functions on {0,…,d−1}\{0,\ldots,d-1\}{0,…,d−1}, with its usual measurable structure and Lebesgue measure dxdxdx. Let QQQ be any probability measure on XXX, so Q(X)=1Q(X)=1Q(X)=1, and let ρ:R×X×X→R\rho:\mathbb R\times X\times X\to\mathbb Rρ:R×X×X→R be any function satisfying all of the following: for every t∈[0,1]t\in[0,1]t∈[0,1] and every x,z∈Xx,z\in Xx,z∈X, ρ(t,x,z)>0\rho(t,x,z)>0ρ(t,x,z)>0; for every t∈[0,1]t\in[0,1]t∈[0,1], the function (x,z)↦ρ(t,x,z)(x,z)\mapsto\rho(t,x,z)(x,z)↦ρ(t,x,z) is jointly measurable; for every t∈[0,1]t\in[0,1]t∈[0,1] and every z∈Xz\in Xz∈X, the function x↦ρ(t,x,z)x\mapsto\rho(t,x,z)x↦ρ(t,x,z) is nonnegative at every xxx, integrable with respect to dxdxdx, and satisfies ∫Xρ(t,x,z) dx=1\int_X\rho(t,x,z)\,dx=1∫X​ρ(t,x,z)dx=1; and for every t∈[0,1]t\in[0,1]t∈[0,1] and every x∈Xx\in Xx∈X, the function z↦ρ(t,x,z)z\mapsto\rho(t,x,z)z↦ρ(t,x,z) is integrable with respect to QQQ. Define p(t,x)=∫Xρ(t,x,z) dQ(z)p(t,x)=\int_X\rho(t,x,z)\,dQ(z)p(t,x)=∫X​ρ(t,x,z)dQ(z), using the real-valued Bochner integral. Then for every t∈[0,1]t\in[0,1]t∈[0,1], p(t,x)≥0p(t,x)\geq0p(t,x)≥0 for every x∈Xx\in Xx∈X, x↦p(t,x)x\mapsto p(t,x)x↦p(t,x) is integrable with respect to dxdxdx, ∫Xp(t,x) dx=1\int_Xp(t,x)\,dx=1∫X​p(t,x)dx=1, and, additionally, p(t,x)>0p(t,x)>0p(t,x)>0 for every x∈Xx\in Xx∈X. Both the hypotheses and the conclusion include the endpoint times 000 and 111; they impose no conditions or conclusion at other times. The pointwise positivity assertions hold everywhere, rather than merely almost everywhere. The case d=0d=0d=0 is included, in which XXX consists of the single empty-coordinate vector; the spatial quantifiers still range over that singleton. No absolute continuity assumption on QQQ is made.

Human review
  • Endorsed by Shuze Chen · Sep 24, 2026

    Confirmed by the moderator at approval.

  • Endorsed by MiltMont · Sep 24, 2026

    Confirmed by the mission captain (proposal self-audit).

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