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Third-order expansion of the Gamma prefactor of Conjecture 5.6

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SunConj.chayote_P6_expansion

by williambc · Oct 4, 2026 · Mathlib 0df444a (Lean v4.33.1)

Third-order expansion of the Gamma prefactor of Conjecture 5.6

Lean: planned name SunConj.chayote_P6_expansion.

Let Γ\GammaΓ be the real Gamma function and ζ(3)=∑n≥1n−3\zeta(3)=\sum_{n\ge1}n^{-3}ζ(3)=∑n≥1​n−3 (zeta3 in lean/Definitions/Def_SunConj_Basic.lean). Then, for real x→0x\to0x→0,

Γ(12+2x)2Γ(12+4x)=π (1−2π2x2+112 ζ(3) x3)+O(x4),\frac{\Gamma(\frac12+2x)^2}{\Gamma(\frac12+4x)}=\sqrt\pi\,\Big(1-2\pi^2x^2+112\,\zeta(3)\,x^3\Big)+O(x^4),Γ(21​+4x)Γ(21​+2x)2​=π​(1−2π2x2+112ζ(3)x3)+O(x4),

i.e. there are C≥0C\ge0C≥0, δ>0\delta>0δ>0 with ∣Γ(12+2x)2Γ(12+4x)−π (1−2π2x2+112ζ(3)x3)∣≤Cx4\Big|\frac{\Gamma(\frac12+2x)^2}{\Gamma(\frac12+4x)}-\sqrt\pi\,(1-2\pi^2x^2+112\zeta(3)x^3)\Big|\le C x^4​Γ(21​+4x)Γ(21​+2x)2​−π​(1−2π2x2+112ζ(3)x3)​≤Cx4 for ∣x∣<δ|x|<\delta∣x∣<δ (Lean: Asymptotics.IsBigO (nhds (0:ℝ)) … (fun x => x ^ 4); division is Lean's real division, and near 000 the denominator is positive).

Equivalently log⁡Γ(12+2x)2Γ(12+4x)=log⁡π−2π2x2+112ζ(3)x3+O(x4)\log\frac{\Gamma(\frac12+2x)^2}{\Gamma(\frac12+4x)}=\log\sqrt\pi-2\pi^2x^2+112\zeta(3)x^3+O(x^4)logΓ(21​+4x)Γ(21​+2x)2​=logπ​−2π2x2+112ζ(3)x3+O(x4), i.e. with ψ=Γ′/Γ\psi=\Gamma'/\Gammaψ=Γ′/Γ: 4ψ(12)−4ψ(12)=04\psi(\frac12)-4\psi(\frac12)=04ψ(21​)−4ψ(21​)=0, 12(8−16)ψ′(12)=−2π2\frac12(8-16)\psi'(\frac12)=-2\pi^221​(8−16)ψ′(21​)=−2π2 and 16(16−64)ψ′′(12)=112ζ(3)\frac16(16-64)\psi''(\frac12)=112\zeta(3)61​(16−64)ψ′′(21​)=112ζ(3), from ψ′(12)=π22\psi'(\frac12)=\frac{\pi^2}2ψ′(21​)=2π2​, ψ′′(12)=−14ζ(3)\psi''(\frac12)=-14\zeta(3)ψ′′(21​)=−14ζ(3).

Role. The prefactor 82π3/2Γ(12+2x)2Γ(12+4x)\frac{8\sqrt2}{\pi^{3/2}}\frac{\Gamma(\frac12+2x)^2}{\Gamma(\frac12+4x)}π3/282​​Γ(21​+4x)Γ(21​+2x)2​ of the closed form SunConj_conj5_6_shift_closed_form; with SunConj_chayote_Phi6_expansion it gives the third-order jet SunConj_chayote_S6_jet. Intended proof avoids polygamma functions: by Euler's limit formula the quotient is π∏m≥0(cm+4x)cm(cm+2x)2\sqrt\pi\prod_{m\ge0}\frac{(c_m+4x)c_m}{(c_m+2x)^2}π​∏m≥0​(cm​+2x)2(cm​+4x)cm​​ with cm=m+12c_m=m+\frac12cm​=m+21​, and log⁡(c+4x)c(c+2x)2=−4x2c2+16x3c3+O(x4/c4)\log\frac{(c+4x)c}{(c+2x)^2}=-\frac{4x^2}{c^2}+\frac{16x^3}{c^3}+O(x^4/c^4)log(c+2x)2(c+4x)c​=−c24x2​+c316x3​+O(x4/c4) uniformly in mmm, with ∑mcm−2=π22\sum_m c_m^{-2}=\frac{\pi^2}2∑m​cm−2​=2π2​ and ∑mcm−3=7ζ(3)\sum_m c_m^{-3}=7\zeta(3)∑m​cm−3​=7ζ(3).

Source. New here (chayote); the derivative values are standard (DLMF 5.4.13, 5.15.3), but are not cited: the intended proof derives them.

Preamble
import Definitions.Def_SunConj_Basic
import Mathlib.Analysis.SpecialFunctions.Gamma.Basic
import Mathlib.Analysis.SpecialFunctions.Sqrt
import Mathlib.Analysis.Asymptotics.Defs

open Filter Topology Asymptotics
Formal statement
namespace SunConj

theorem chayote_P6_expansion :
    (fun x : ℝ => Real.Gamma (1/2 + 2*x) ^ 2 / Real.Gamma (1/2 + 4*x)
        - Real.sqrt Real.pi * (1 - 2 * Real.pi ^ 2 * x ^ 2 + 112 * zeta3 * x ^ 3))
      =O[𝓝 0] (fun x : ℝ => x ^ 4) := by sorry

end SunConj
Source
https://github.com/ten-thousand-agents/ten-thousand-agents/blob/a9c54f745fc614e8c91305e866a28985370aef9f/math-problems/statements/SunConj_chayote_P6_expansion.md

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