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Exact finite reset-ledger balance

Proved
WindingDynamics.resetLedgerBalance

by lisamegawatts · Sep 19, 2026 · Mathlib c5ea003 (Lean v4.30.0)

algebraic-topologydynamical-systemsphase-slipsreset-ledgerwinding-number

A coherent reset ledger stores successive integer edge-turn states and defines each reset as next state minus current state. The sum of resets telescopes on every edge to the final-minus-initial turn state. Consequently, for every certified closed integer cycle, the final-minus-initial cycle winding equals the sum of the cycle pairings with all registered resets. The orientation is right/next minus left/current, and only indices below the registered number of steps occur.

Preamble
import Definitions.Def_WindingDynamics_CoreV1
Formal statement
theorem WindingDynamics.resetLedgerBalance : WindingDynamics.ResetLedgerBalanceGate := by sorry
Source
MonumentalSystems/LeanProofs, CircleFundamentalGroupWindingV1 and FiniteTorusPrincipalResetEventV1 at commit b656238b73d5f0f74515f6574a1dcb4e0216129f (2026-09-18); theorem contract independently reconstructed over Mathlib 4.30.
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What the Lean code literally says, in plain math · gpt-5.6-sol

The theorem is a conjunction of two telescoping identities. First, for every small edge type EEE, every ledger consisting of a natural number nnn and integer-valued edge cochains Ti:E→ZT_i:E\to\mathbb ZTi​:E→Z for all natural iii, and every edge e∈Ee\in Ee∈E, one has

∑i=0n−1(Ti+1(e)−Ti(e))=Tn(e)−T0(e).\sum_{i=0}^{n-1}\bigl(T_{i+1}(e)-T_i(e)\bigr)=T_n(e)-T_0(e).i=0∑n−1​(Ti+1​(e)−Ti​(e))=Tn​(e)−T0​(e).

Second, for every small vertex type VVV, every finite small edge type EEE, every arbitrary coefficient function b:E×V→Zb:E\times V\to\mathbb Zb:E×V→Z, every such ledger, and every integer chain c:E→Zc:E\to\mathbb Zc:E→Z equipped with the certificate ∑ec(e)b(e,v)=0\sum_e c(e)b(e,v)=0∑e​c(e)b(e,v)=0 for every vvv, one has

∑eTn(e)c(e)−∑eT0(e)c(e)=∑i=0n−1∑e(Ti+1(e)−Ti(e))c(e).\sum_e T_n(e)c(e)-\sum_e T_0(e)c(e) =\sum_{i=0}^{n-1}\sum_e\bigl(T_{i+1}(e)-T_i(e)\bigr)c(e).e∑​Tn​(e)c(e)−e∑​T0​(e)c(e)=i=0∑n−1​e∑​(Ti+1​(e)−Ti​(e))c(e).

The reset orientation is next state minus current state, and the left side is final winding minus initial winding. When n=0n=0n=0, both sides of each identity are zero; values TiT_iTi​ for i>ni>ni>n are unrestricted and unused. If EEE is empty, the first universal claim is vacuous because it quantifies an edge, while the second identity consists of zero sums. If VVV is empty, the certified closedness condition is vacuous. No incidence or orientation laws are required of bbb, and neither VVV nor the first assertion’s EEE is required to be finite. The second identity is algebraic and does not use the supplied closedness certificate, so it would state the same equality for an arbitrary chain.

Human review
  • Endorsed by Shuze Chen · Sep 22, 2026

  • Endorsed by lisamegawatts · Sep 22, 2026

    Confirmed by the mission captain (proposal self-audit).

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