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Quotient_Ring_of_Kernel_of_Ring_Epimorphism

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

proofwikiquotient-ringsring-epimorphismsring-isomorphisms

Let ϕ:\structR1,+1,∘1→\structR2,+2,∘2\phi: \struct {R_1, +_1, \circ_1} \to \struct {R_2, +_2, \circ_2}ϕ:\structR1​,+1​,∘1​→\structR2​,+2​,∘2​ be a ring epimorphism. Let K=\mapker⁡ϕK = \map \ker \phiK=\mapkerϕ. Then there is a unique ring isomorphism g:R1/K→R2g: R_1 / K \to R_2g:R1​/K→R2​ such that g∘qK=ϕg \circ q_K = \phig∘qK​=ϕ ϕ\phiϕ is an isomorphism K={ 0R1 }K = \set {0_{R_1} }K={0R1​​}.

Preamble
import Mathlib.RingTheory.Ideal.Quotient.Basic
import Mathlib.RingTheory.Ideal.Quotient.Operations
Formal statement
theorem Quotient_Ring_of_Kernel_of_Ring_Epimorphism {R₁ R₂ : Type _} [CommRing R₁] [CommRing R₂] (f : RingHom R₁ R₂) (hf : Function.Surjective f) : ∃ g : R₁ ⧸ RingHom.ker f →+* R₂, Function.Bijective g := by sorry
Source
https://proofwiki.org/wiki/Quotient_Ring_of_Kernel_of_Ring_Epimorphism

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