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Closability is equivalent to absolute continuity

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QAlgorithms.Papers.Independent.Intakethird100.P38.closable_iff_absolute_continuity

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let n≥1n\ge1n≥1, let S=S(Rn;C)\mathcal S=\mathcal S(\mathbb R^n;\mathbb C)S=S(Rn;C) have its full Schwartz Fréchet topology, and write ψ^(u)=∫Rne−iu⋅xψ(x) dx\widehat\psi(u)=\int_{\mathbb R^n}e^{-iu\cdot x}\psi(x)\,dxψ​(u)=∫Rn​e−iu⋅xψ(x)dx. Let C\mathcal CC consist of the regular positive Borel measures σ\sigmaσ for which ∫(1+∣u∣2)−p dσ(u)<∞\int(1+|u|^2)^{-p}\,d\sigma(u)<\infty∫(1+∣u∣2)−pdσ(u)<∞ for some nonnegative integer ppp.

For σ∈C\sigma\in\mathcal Cσ∈C, put qσ(ψ)=∫∣ψ^∣2 dσq_\sigma(\psi)=\int|\widehat\psi|^2\,d\sigmaqσ​(ψ)=∫∣ψ​∣2dσ. Closability is taken in the ambient space L2(dx)L^2(dx)L2(dx): whenever sk∈Ss_k\in\mathcal Ssk​∈S tends to zero in L2(dx)L^2(dx)L2(dx) and qσ(sk−sl)→0q_\sigma(s_k-s_l)\to0qσ​(sk​−sl​)→0 as both indices tend to infinity, one has qσ(sk)→0q_\sigma(s_k)\to0qσ​(sk​)→0. Then

qσ is closable in L2(dx)⟺σ≪dx.q_\sigma\text{ is closable in }L^2(dx)\quad\Longleftrightarrow\quad\sigma\ll dx.qσ​ is closable in L2(dx)⟺σ≪dx.

This keeps both implications, without assuming the existence of the source proof's auxiliary operator or kernel.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P38
Formal statement
noncomputable section

namespace QAlgorithms.Papers.Independent.Intakethird100.P38

open MeasureTheory Filter

open scoped Topology ComplexConjugate ENNReal

/-- Theorem 4.2, PDF pp.11--13: both directions of closability in the ambient
Lebesgue L2 space. The unfinished converse proof is not a premise. -/
theorem closable_iff_absolute_continuity (n : ℕ) (hn : 0 < n)
    (σ : Measure (SpectralDomain n)) (hσ : InC σ) :
    Closable (spectralQ σ) ↔ σ ≪ (volume : Measure (SpectralDomain n)) := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P38

end
Source
Stochastic processes induced by singular operators, arXiv:1109.5273v1, PDF p. 12, Theorem 4.2: closability iff absolute continuity
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What the Lean code literally says, in plain math · gpt-6.1-sol

For every positive integer nnn, let X=RFin⁡nX=\mathbb R^{\operatorname{Fin}n}X=RFinn be Euclidean space, and let σ\sigmaσ be a regular measure on XXX satisfying ∫X(1+∥u∥2)−p dσ(u)<∞\int_X(1+\|u\|^2)^{-p}\,d\sigma(u)<\infty∫X​(1+∥u∥2)−pdσ(u)<∞ for some natural number ppp, with p=0p=0p=0 allowed. For each complex-valued Schwartz function ψ\psiψ, define

ψ^(u)=∫Xe−i⟨u,x⟩ψ(x) dx,q(ψ)=toReal⁡ ⁣(∫X ⁣ ⁣−∣ψ^(u)∣2 dσ(u)),\widehat\psi(u)=\int_X e^{-i\langle u,x\rangle}\psi(x)\,dx, \qquad q(\psi)=\operatorname{toReal}\!\left(\int_X^{\!\!-}|\widehat\psi(u)|^2\,d\sigma(u)\right),ψ​(u)=∫X​e−i⟨u,x⟩ψ(x)dx,q(ψ)=toReal(∫X−​∣ψ​(u)∣2dσ(u)),

where the integral inside toReal⁡\operatorname{toReal}toReal is extended nonnegative, and toReal⁡(+∞)=0\operatorname{toReal}(+\infty)=0toReal(+∞)=0. For a function ggg, let [g]du[g]_{du}[g]du​ denote its L2L^2L2 class for Euclidean volume when it belongs to L2L^2L2, and zero otherwise. Then σ\sigmaσ is absolutely continuous with respect to Euclidean volume if and only if the following sequence property holds: for every sequence (sk)k∈N(s_k)_{k\in\mathbb N}(sk​)k∈N​ of complex-valued Schwartz functions, if ∥[sk]du∥→0\|[s_k]_{du}\|\to0∥[sk​]du​∥→0 and

∀ε>0  ∃N∈N  ∀k,l≥N,q(sk−sl)<ε,\forall\varepsilon>0\;\exists N\in\mathbb N\;\forall k,l\ge N,\qquad q(s_k-s_l)<\varepsilon,∀ε>0∃N∈N∀k,l≥N,q(sk​−sl​)<ε,

then q(sk)→0q(s_k)\to0q(sk​)→0. Absolute continuity here means that every measurable set of volume zero has σ\sigmaσ-measure zero.

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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