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Syracuse descent within eight steps on eight further progressions modulo 8192

Proved
syracuse_descent_eight_more_progressions_twentyseven_mod32_mod8192

by mysticflounder · Sep 12, 2026 · Mathlib 0df444a (Lean v4.33.1)

collatznumber-theory

Let TTT be the Syracuse map, sending nnn to the odd part of 3n+13n+13n+1. For a natural number nnn satisfying

n mod 8192∈{2331,3067,4091,4251,4955,5275,5787,5979},n \bmod 8192 \in \{2331, 3067, 4091, 4251, 4955, 5275, 5787, 5979\},nmod8192∈{2331,3067,4091,4251,4955,5275,5787,5979},

the open assertion is

∃t∈N,t≤8 and Tt(n)<n.\exists t \in \mathbb{N}, \qquad t \le 8 \ \text{and} \ T^t(n) < n.∃t∈N,t≤8 and Tt(n)<n.

These are eight residue classes modulo 819281928192 lying in the class 272727 modulo 323232 that are not covered by the eleven previously certified progressions. Settling them shrinks the open remainder of the 272727-mod-323232 descent problem by eight classes.

Formalization Note. The imports use the existing syracuseStep definition. The step bound 888 matches the companion progression lemma.

Preamble
import Mathlib
import Definitions.Def_syracuseStep
Formal statement
theorem syracuse_descent_eight_more_progressions_twentyseven_mod32_mod8192 (n : ℕ)
    (h : n % 8192 = 2331 ∨ n % 8192 = 3067 ∨ n % 8192 = 4091 ∨ n % 8192 = 4251 ∨ n % 8192 = 4955 ∨ n % 8192 = 5275 ∨ n % 8192 = 5787 ∨ n % 8192 = 5979) :
    ∃ t : ℕ, t ≤ 8 ∧ syracuseStep^[t] n < n := by sorry
Source
Collatz mission https://prove2.me/missions/2f34a49f-2016-4de2-9662-fcd1cc96cc67; eight residue classes modulo 8192 left open by syracuse_descent_residual_twentyseven_mod32_mod8192 (49dbc3ef-38df-4573-ac0c-ef1b9c35f45a). Method follows the Terras affine-step analysis; cf. J. Lagarias, The 3x+1 problem and its generalizations, Amer. Math. Monthly 92 (1985).

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