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Fixed-cardinality union convolution is disjoint convolution

Proved
ThreeSum.Subset.unionConvolution_eq_disjointConvolution

by wurtle · Oct 14, 2026 · Mathlib 0df444a (Lean v4.33.1)

3sumalgorithmsfine-grained-complexitythree-sum-1962word-ram

Let α\alphaα have decidable equality and let f,gf,gf,g be integer-valued functions on its finite subsets. Suppose f(S)≠0f(S)\ne0f(S)=0 implies ∣S∣=a|S|=a∣S∣=a and g(T)≠0g(T)\ne0g(T)=0 implies ∣T∣=b|T|=b∣T∣=b, for fixed a,b∈Na,b\in\mathbb Na,b∈N. For a finite set QQQ with ∣Q∣=a+b|Q|=a+b∣Q∣=a+b,

∑S,T⊆QS∪T=Qf(S)g(T)=∑S⊆Qf(S)g(Q∖S).\sum_{\substack{S,T\subseteq Q\\S\cup T=Q}}f(S)g(T)=\sum_{S\subseteq Q}f(S)g(Q\setminus S).S,T⊆QS∪T=Q​∑​f(S)g(T)=S⊆Q∑​f(S)g(Q∖S).

This converts exact-union convolution into the disjoint subset convolution needed by the fixed-cardinality counting construction, even when the coefficients are signed integers.

Preamble
import Aesop
import Definitions.Def_ThreeSum1962Source_Bundle01
import Lean.Elab.Tactic.Omega
import Mathlib.Algebra.BigOperators.Group.Finset.Powerset
import Mathlib.Algebra.BigOperators.Group.Finset.Sigma
import Mathlib.Algebra.BigOperators.Ring.Finset
import Mathlib.Algebra.Order.BigOperators.Group.Finset
import Mathlib.Data.Finset.Card
import Mathlib.Tactic.ByContra
import Mathlib.Tactic.Ring
import Mathlib.Tactic.SplitIfs


set_option autoImplicit false
set_option relaxedAutoImplicit false
set_option Elab.async false

universe u_1
Formal statement
theorem ThreeSum.Subset.unionConvolution_eq_disjointConvolution : ∀ {α : Type u_1} [inst : DecidableEq.{u_1 + 1} α] (f g : Finset.{u_1} α → Int) (q : Finset.{u_1} α) (a b : Nat)
  (hf :
    ∀ (s : Finset.{u_1} α),
      @Ne.{1} Int (f s) (@OfNat.ofNat.{0} Int (nat_lit 0) (@instOfNat (nat_lit 0))) →
        @Eq.{1} Nat (@Finset.card.{u_1} α s) a)
  (hg :
    ∀ (v : Finset.{u_1} α),
      @Ne.{1} Int (g v) (@OfNat.ofNat.{0} Int (nat_lit 0) (@instOfNat (nat_lit 0))) →
        @Eq.{1} Nat (@Finset.card.{u_1} α v) b)
  (hq : @Eq.{1} Nat (@Finset.card.{u_1} α q) (@HAdd.hAdd.{0, 0, 0} Nat Nat Nat (@instHAdd.{0} Nat instAddNat) a b)),
  @Eq.{1} Int (@ThreeSum.Subset.unionConvolution.{u_1} α inst f g q)
    (@ThreeSum.Subset.disjointConvolution.{u_1} α inst f g q) := by
  sorry
Source
https://github.com/c0ldzy17/three-sum-lean/blob/2b639655e07421b9ac743de9090459bab473a7c0/Submission/ThreeSum/Subset.lean#L191-L239

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