Injective boundary determines every bibundle by its type
OpenQAlgorithms.Papers.Independent.Intakethird100.P93.corollary_3_4Let be a topological crossed module, with continuous action . Thus and . Put and give both and their quotient topologies. Assume their quotient projections admit continuous local sections. All actions, structure maps and isomorphisms below are continuous, all principal bundles are locally trivial, and a bispace has a nonempty principal homogeneous underlying right space.
Assume . The canonical projection identifies topologically and as a group with . For every -bibundle with structure map and type map , the canonical map gives
The second isomorphism preserves projection, right action and structure map. Both conclusions depend on the trivial-kernel assumption; no compactness or nonempty-base assumption is added.
Source correction: additionally require that the canonical map is topologically inducing, so the quotient topology agrees with the subspace topology on . The printed local-section assumptions alone do not imply this; see correction.printed/changed/why and MODERATION-r1.md.
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P93
namespace QAlgorithms.Papers.Independent.Intakethird100.P93
universe u
variable {G H : Type u} [Group G] [TopologicalSpace G] [IsTopologicalGroup G]
[Group H] [TopologicalSpace H] [IsTopologicalGroup H]
variable (C : CrossedModule G H)
/-- Corollary 3.4, PDF p.11, both conclusions. With trivial kernel the
canonical G→G/ker(t)=t(G) is a topological group isomorphism, and the actual
map p↦(pi(p),psi(p)) identifies every bibundle with the type pullback.
Source correction (topology): Printed: the claim uses the p.4 local-section
assumptions and identifies t(G)=G/ker(t) on p.7. Changed: htop explicitly
identifies the quotient topology with the image subspace topology. Why: those
local-section assumptions alone allow the identity R_discrete -> R_usual;
its inverse is not continuous. No closed-image condition is added.
-/
theorem corollary_3_4 (htop : Topology.IsInducing (QuotientGroup.kerLift C.t))
{M P : Type u} [TopologicalSpace M] [TopologicalSpace P]
(hker : C.t.ker = ⊥) (B : Bibundle C M P) :
(∃ e : G ≃ₜ (G ⧸ C.t.ker),
(∀ g, e g = QuotientGroup.mk g) ∧ ∀ g k, e (g * k) = e g * e k) ∧
(∃ phi : C(M, TypeGroup C),
(∀ p, phi (B.bundle.proj p) = typeProjection C (B.psi p)) ∧
∃ e : P ≃ₜ TypePullback C phi,
(∀ p, (e p).val = (B.bundle.proj p, B.psi p)) ∧
(∀ p g, (e (B.bundle.right.act p g)).val =
(B.bundle.proj p, B.psi p * C.t g))) := by sorry
end QAlgorithms.Papers.Independent.Intakethird100.P93
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What the Lean code literally says, in plain math · gpt-6.1-sol
Let be topological groups in a common universe, and let consist of a continuous homomorphism and a homomorphism with continuous evaluation, satisfying and for all . Put , , and let be the quotient map. Assume, as part of , that each of and has, on an open neighbourhood of every point of its codomain, a continuous section whose composition with the quotient map is the identity. Assume also that the topology on is induced by into , and that . Let be arbitrary topological spaces in the same universe, and let supply a continuous right -action , an invariant continuous projection , equivariant local homeomorphisms over an open neighbourhood of every base point, with acting by multiplication on the second coordinate, and a continuous map with . Then both of the following hold: there is a homeomorphism such that for every and for every ; and there is a continuous map with for every , together with a homeomorphism
to this subspace of , satisfying for every and for every and . The base is allowed to be empty.
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.