Eq. (21): $\frac1{M_C}\sum_k g(\eta\beta_k\bar N_k)=g(\eta\beta\bar N)$ · Prove2Me

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Initializing...

Eq. (21): $\frac1{M_C}\sum_k g(\eta\beta_k\bar N_k)=g(\eta\beta\bar N)$ · Prove2Me