Equation (20b): $J_{2g_A}\tilde K_\lambda J_{2g_B}=\tilde K_\lambda$ (corrected: requires $\lambda\ne0$)

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Equation (20b): $J_{2g_A}\tilde K_\lambda J_{2g_B}=\tilde K_\lambda$ (corrected: requires $\lambda\ne0$) · Prove2Me