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Corollary 3.4: IID randomness dilution

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QAlgorithms.Papers.Independent.Intakethird100.P42.iidRandomnessDilution

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let qqq be a probability distribution on a finite nonempty alphabet YYY. Independently sample a codebook D=(Y1,…,YM)D=(Y_1,\ldots,Y_M)D=(Y1​,…,YM​) from q⊗nq^{\otimes n}q⊗n. For each fixed codebook, let q~D\widetilde q_Dq​D​ be the distribution of YWY_WYW​ when WWW is sampled uniformly from [M]={1,…,M}[M]=\{1,\ldots,M\}[M]={1,…,M} independently of that book. Thus q~D\widetilde q_Dq​D​ is the empirical law conditional on the book.

There is an absolute constant κ>0\kappa>0κ>0 and a constant c>0c>0c>0 depending only on qqq such that, for every ϵ,δ>0\epsilon,\delta>0ϵ,δ>0, all sufficiently large positive nnn, and every integer M≥1M\ge1M≥1, with γ=2n[H(q)+cδ]\gamma=2^{n[H(q)+c\delta]}γ=2n[H(q)+cδ],

Pr⁡D ⁣{∥q⊗n−q~D∥1≥2ϵ}≤2γexp⁡ ⁣(−κMϵ2γ).\Pr_D\!\left\{\left\|q^{\otimes n}-\widetilde q_D\right\|_1\ge2\epsilon\right\}\le2\gamma\exp\!\left(-\frac{\kappa M\epsilon^2}{\gamma}\right).DPr​{​q⊗n−q​D​​1​≥2ϵ}≤2γexp(−γκMϵ2​).

The blocklength threshold is independent of MMM; Shannon entropy is in bits and the norm is the full sum of absolute differences.

This quantifies IID randomness dilution without identifying the empirical conditional law with its unconditional average.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P42
Formal statement
noncomputable section

namespace QAlgorithms.Papers.Independent.Intakethird100.P42

open scoped BigOperators ComplexConjugate ENNReal

open Filter

open QAlgorithms.Papers.Independent.Dependency50.P07

open QAlgorithms.Papers.Independent.Gap48.P20

open QAlgorithms.Papers.Independent.Information100.P27 (IsProbability shannon)

attribute [local instance] Classical.decEq Classical.propDecidable

/-- PDF pp.6--7, Corollary 3.4: IID randomness dilution. kappa is absolute,
c depends only on q, and the threshold does not depend on M. -/
theorem iidRandomnessDilution :
    ∃ kappa : ℝ, 0 < kappa ∧
      ∀ (Y : Type) [Fintype Y] [Nonempty Y] (q : Y → ℝ), IsProbability q →
        ∃ c : ℝ, 0 < c ∧ ∀ eps > (0 : ℝ), ∀ delta > (0 : ℝ), ∃ N : ℕ,
          ∀ n ≥ N, 1 ≤ n → ∀ M : ℕ, 1 ≤ M →
            let gamma := (2 : ℝ) ^ ((n : ℝ) * (shannon q + c * delta))
            bookProbability q n M (fun book => 2 * eps ≤ dilutionError q n M book) ≤
              2 * gamma * Real.exp (-kappa * M * eps ^ 2 / gamma) := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P42

end
Source
Channel simulation with quantum side information, arXiv:quant-ph/0611008v1, PDF p. 6, Corollary 3.4: IID randomness dilution
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What the Lean code literally says, in plain math · gpt-6.1-sol

There exists a real constant κ>0\kappa>0κ>0 such that, for every finite nonempty type YYY and every probability function q:Y→Rq:Y\to\mathbb Rq:Y→R, meaning q(y)≥0q(y)\ge0q(y)≥0 and ∑yq(y)=1\sum_yq(y)=1∑y​q(y)=1, there exists a real constant c>0c>0c>0 such that for every ε>0\varepsilon>0ε>0 and δ>0\delta>0δ>0 there is a natural number NNN for which the following holds for every n≥Nn\ge Nn≥N with n≥1n\ge1n≥1 and every natural number M≥1M\ge1M≥1. Set H(q)=−∑yq(y)log⁡2q(y)H(q)=-\sum_yq(y)\log_2q(y)H(q)=−∑y​q(y)log2​q(y) and γ=2n(H(q)+cδ)\gamma=2^{n(H(q)+c\delta)}γ=2n(H(q)+cδ). Then

∑b:{0,…,M−1}→Yn2ε≤∑y∈Yn∣∏j<nq(yj)−#{i<M:bi=y}/M∣ ∏i<M∏j<nq((bi)j)≤2γexp⁡ ⁣(−κMε2γ).\sum_{\substack{b:\{0,\ldots,M-1\}\to Y^n\\ 2\varepsilon\le \sum_{y\in Y^n}\left|\prod_{j<n}q(y_j)-\#\{i<M:b_i=y\}/M\right|}} \ \prod_{i<M}\prod_{j<n}q((b_i)_j) \le 2\gamma\exp\!\left(-\frac{\kappa M\varepsilon^2}{\gamma}\right).b:{0,…,M−1}→Yn2ε≤∑y∈Yn​∣∏j<n​q(yj​)−#{i<M:bi​=y}/M∣​∑​ i<M∏​j<n∏​q((bi​)j​)≤2γexp(−γκMε2​).

The constant κ\kappaκ is chosen before Y,qY,qY,q, and ccc before ε,δ\varepsilon,\deltaε,δ. Zero values of qqq are allowed, with the logarithm convention log⁡20=0\log_2 0=0log2​0=0; neither ε\varepsilonε nor δ\deltaδ has an upper bound in the hypotheses.

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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