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At a candidate u, with Roy's strong six exponentials theorem as hypothesis: for 4 ≤ k < l with l ∈ {k+1, k+2, 2k−1, 2k, 2k+1, 3k}, u^k and u^l are not both in ℒ̃

Proved
DiazModulus.candidate_power_pair_not_both_mem_logAlgTilde

by carlok · Oct 8, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Here L\mathcal{L}L is the set of logarithms of algebraic numbers, and L~\widetilde{\mathcal{L}}L is the Q‾\overline{\mathbb{Q}}Q​-vector space spanned by 111 and L\mathcal{L}L. Roy's strong six exponentials theorem is carried as the hypothesis hSSE: if x1,x2x_1, x_2x1​,x2​ are Q‾\overline{\mathbb{Q}}Q​-linearly independent and so are y1,y2,y3y_1, y_2, y_3y1​,y2​,y3​, then one of the six products xiyjx_iy_jxi​yj​ is not in L~\widetilde{\mathcal{L}}L.

Let uuu be a candidate for Diaz's conjecture (DiazModulus.IsCandidate) and 4≤k<l4 \le k < l4≤k<l with l∈{k+1,k+2,2k−1,2k,2k+1,3k}l \in \{k + 1, k + 2, 2k - 1, 2k, 2k + 1, 3k\}l∈{k+1,k+2,2k−1,2k,2k+1,3k}. Then uku^kuk and ulu^lul are not both in L~\widetilde{\mathcal{L}}L. For example, no two consecutive powers uk,uk+1u^k, u^{k+1}uk,uk+1 with k≥4k \ge 4k≥4 are both in L~\widetilde{\mathcal{L}}L. It concerns candidates, so it is vacuous if Diaz's conjecture holds.

Proof. ρ=∣u∣2\rho = |u|^2ρ=∣u∣2 is algebraic and uuu is transcendental (DiazModulus.hermite_lindemann_holds), so powers of uuu with distinct integer exponents are Q‾\overline{\mathbb{Q}}Q​-independent. By conjugation (DiazModulus.logAlgTilde_conj_stable), un∈L~u^n \in \widetilde{\mathcal{L}}un∈L gives u−n=ρ−n un‾∈L~u^{-n} = \rho^{-n}\,\overline{u^n} \in \widetilde{\mathcal{L}}u−n=ρ−nun∈L, so us∈L~u^s \in \widetilde{\mathcal{L}}us∈L for s∈{0,±1,±k,±l}s \in \{0, \pm1, \pm k, \pm l\}s∈{0,±1,±k,±l}. In each case x=(ua)a∈Ax = (u^a)_{a \in A}x=(ua)a∈A​, y=(ub)b∈By = (u^b)_{b \in B}y=(ub)b∈B​ is a 2×32 \times 32×3 configuration in L~\widetilde{\mathcal{L}}L, against hSSE: l=k+1l = k + 1l=k+1: A={0,1}A = \{0, 1\}A={0,1}, B={−1,0,k}B = \{-1, 0, k\}B={−1,0,k}; l=k+2l = k + 2l=k+2: {0,2}\{0, 2\}{0,2}, {−1,k,−k−2}\{-1, k, -k - 2\}{−1,k,−k−2}; l=2k−1l = 2k - 1l=2k−1: {0,k−1}\{0, k - 1\}{0,k−1}, {1,−k,k}\{1, -k, k\}{1,−k,k}; l=2kl = 2kl=2k: {0,k}\{0, k\}{0,k}, {0,−k,k}\{0, -k, k\}{0,−k,k}; l=2k+1l = 2k + 1l=2k+1: {0,k+1}\{0, k + 1\}{0,k+1}, {−1,−k,k}\{-1, -k, k\}{−1,−k,k}; l=3kl = 3kl=3k: {0,2k}\{0, 2k\}{0,2k}, {−k,k,−3k}\{-k, k, -3k\}{−k,k,−3k}.

Novelty. Not asserted: each case is one substitution in Diaz (2007): l=k+1l = k + 1l=k+1 in Cor. 2(P)(1); l=k+2l = k + 2l=k+2, 2k−12k - 12k−1, 2k+12k + 12k+1 in Th. 7(1); l=2kl = 2kl=2k and 3k3k3k in Cor. 5(1) and 5(2), with λ=uk\lambda = u^kλ=uk and uˉk=ρku−k\bar u^k = \rho^k u^{-k}uˉk=ρku−k. Diaz does not state them at a candidate.

Preamble
import Definitions.Def_DiazModulus
Formal statement
open Complex ComplexConjugate

namespace DiazModulus

theorem candidate_power_pair_not_both_mem_logAlgTilde
    (hSSE : ∀ (x : Fin 2 → ℂ) (y : Fin 3 → ℂ),
      LinearIndependent (↥Qbar) x → LinearIndependent (↥Qbar) y →
      ¬ (∀ i j, x i * y j ∈ LogAlgTilde))
    {u : ℂ} (h : IsCandidate u) (k l : ℕ) (hk : 4 ≤ k) (hkl : k < l)
    (hl : l = k + 1 ∨ l = k + 2 ∨ l = 2 * k - 1 ∨ l = 2 * k ∨ l = 2 * k + 1 ∨ l = 3 * k) :
    ¬ (u ^ k ∈ LogAlgTilde ∧ u ^ l ∈ LogAlgTilde) := by
  sorry

end DiazModulus
Source
Each case is one substitution in G. Diaz, Produits et quotients de combinaisons linéaires de logarithmes de nombres algébriques : conjectures et résultats partiels, J. Théor. Nombres Bordeaux 19 (2007), 373–391: Cor. 2(P)(1) (p. 381), Th. 7(1) (p. 390), Cor. 5(1)-(2) (p. 383). Roy's strong six exponentials theorem (D. Roy, Matrices whose coefficients are linear forms in logarithms, J. Number Theory 41 (1992), 22–47, Cor. 2) is carried as a hypothesis. Formal proof: Diaz modulus mission, 8 October 2026 (C. Perassi).

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