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The uniform four-qubit erasure-code source admits (2,1)

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QAlgorithms.Papers.Independent.Intakethird100.P11.erasure_ratePair

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let C⊂(C2)⊗4\mathcal C\subset(\mathbb C^2)^{\otimes4}C⊂(C2)⊗4 be the span of the following orthonormal vectors:

∣0000⟩+∣1111⟩2,∣0011⟩+∣1100⟩2,∣0101⟩+∣1010⟩2,∣1001⟩+∣0110⟩2.\frac{|0000\rangle+|1111\rangle}{\sqrt2},\quad \frac{|0011\rangle+|1100\rangle}{\sqrt2},\quad \frac{|0101\rangle+|1010\rangle}{\sqrt2},\quad \frac{|1001\rangle+|0110\rangle}{\sqrt2}.2​∣0000⟩+∣1111⟩​,2​∣0011⟩+∣1100⟩​,2​∣0101⟩+∣1010⟩​,2​∣1001⟩+∣0110⟩​.

The source draws a Haar-uniform unit vector from the whole four-dimensional subspace C\mathcal CC, gives Alice its first two qubits and Bob its last two, and repeats this independently at each position. Then

(RA,RB)=(2,1) is achievable.(R_A,R_B)=(2,1)\text{ is achievable}.(RA​,RB​)=(2,1) is achievable.

An achievable pair uses independent blind local CPTP encoders, one noiseless quantum link from each sender, and a joint CPTP decoder, without supplied shared entanglement or side messages. For every δ,ϵ>0\delta,\epsilon>0δ,ϵ>0, every sufficiently large positive integer blocklength nnn admits positive compressed dimensions dA,dBd_A,d_BdA​,dB​ with log⁡2(dA)/n≤RA+δ\log_2(d_A)/n\le R_A+\deltalog2​(dA​)/n≤RA​+δ, log⁡2(dB)/n≤RB+δ\log_2(d_B)/n\le R_B+\deltalog2​(dB​)/n≤RB​+δ, and ensemble-average pure-input overlap with the reconstructed density operator at least 1−ϵ1-\epsilon1−ϵ. Draws are independent and identically distributed; this is squared fidelity, without a purifying reference.

Uniformity includes all superpositions in C\mathcal CC, and is realized by the first column of normalized Haar U(4)U(4)U(4) followed by the displayed code-space isometry. This gives an achievable point; optimality is left open.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P11
Formal statement
noncomputable section

namespace QAlgorithms.Papers.Independent.Intakethird100.P11

open MeasureTheory Filter

open scoped BigOperators ComplexConjugate Matrix

open QAlgorithms.Papers.Independent.Dependency50.P19 (both)

open QAlgorithms.Papers.Independent.Information100.P27 (shannon)

attribute [local instance] Classical.propDecidable Classical.decEq

/-- PDF p.5, Erasure codes example: the full continuous uniform source admits (2,1).
No claim of optimality or restriction to a finite codeword ensemble is made. -/
theorem erasure_ratePair : DistributedAchievable (fun c => erasureFidelity c) 2 1 := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P11

end
Source
On the distributed compression of quantum information, arXiv:quant-ph/0403042v3, PDF p. 5, Section II: erasure-code example admits (2,1)
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What the Lean code literally says, in plain math · gpt-6.1-sol

For every δ>0\delta>0δ>0 and every ε>0\varepsilon>0ε>0, there exists a natural number NNN such that, for every natural number n>Nn>Nn>N, there are positive natural numbers dA,dBd_A,d_BdA​,dB​ and a distributed block code consisting of separate encoding channels EA,EBE_A,E_BEA​,EB​ from two length-nnn four-dimensional registers to dimensions dA,dBd_A,d_BdA​,dB​, followed by a decoding channel DDD back to the original registers, such that

log⁡2dAn≤2+δ,log⁡2dBn≤1+δ,1−ε≤∫U(4)nRe⁡tr⁡ ⁣(Pw D((EA⊗EB)(Pw))) dH⊗n(w).\frac{\log_2d_A}{n}\le2+\delta,\qquad \frac{\log_2d_B}{n}\le1+\delta,\qquad 1-\varepsilon\le \int_{U(4)^n} \operatorname{Re}\operatorname{tr}\!\left(P_w\, D\bigl((E_A\otimes E_B)(P_w)\bigr)\right)\,dH^{\otimes n}(w).nlog2​dA​​≤2+δ,nlog2​dB​​≤1+δ,1−ε≤∫U(4)n​Retr(Pw​D((EA​⊗EB​)(Pw​)))dH⊗n(w).

Here every channel admits a finite Kraus representation X↦∑jKjXKj†X\mapsto\sum_jK_jXK_j^\daggerX↦∑j​Kj​XKj†​ with ∑jKj†Kj=1\sum_jK_j^\dagger K_j=1∑j​Kj†​Kj​=1, and HHH is normalized Haar measure. For w=(U0,…,Un−1)w=(U_0,\ldots,U_{n-1})w=(U0​,…,Un−1​), the matrix PwP_wPw​ is VwVw†V_wV_w^\daggerVw​Vw†​, where Vw(a,b)=∏tv(Ut)(at,bt)V_w(a,b)=\prod_t v(U_t)(a_t,b_t)Vw​(a,b)=∏t​v(Ut​)(at​,bt​) and

v(U)=U00(e00+e33)+U10(e03+e30)+U20(e11+e22)+U30(e21+e12)2;v(U)=\frac{ U_{00}(e_{00}+e_{33})+U_{10}(e_{03}+e_{30}) +U_{20}(e_{11}+e_{22})+U_{30}(e_{21}+e_{12}) }{\sqrt2};v(U)=2​U00​(e00​+e33​)+U10​(e03​+e30​)+U20​(e11​+e22​)+U30​(e21​+e12​)​;

the eabe_{ab}eab​ are coordinate unit vectors.

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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