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Divergence theorem on a box: ∫V∇⋅F=∮∂VF⋅dS\int_V\nabla\cdot F=\oint_{\partial V}F\cdot d\mathbf S∫V​∇⋅F=∮∂V​F⋅dS

Proved
ContinuityEqWiki.integral_div_eq_boxFlux

by Lucas · Oct 9, 2026 · Mathlib 0df444a (Lean v4.33.1)

continuity-equationmathematical-physics

Let V=[a,b]=∏i=02[ai,bi]⊂R3V=[a,b]=\prod_{i=0}^{2}[a_i,b_i]\subset\mathbb R^3V=[a,b]=∏i=02​[ai​,bi​]⊂R3 be a closed box with a≤ba\le ba≤b coordinatewise, and let F:R3→R3F:\mathbb R^3\to\mathbb R^3F:R3→R3 be a continuously differentiable vector field. Then

∫V∇⋅F(x) dx=∮∂VF⋅dS,\int_V \nabla\cdot F(x)\,dx=\oint_{\partial V}F\cdot d\mathbf S,∫V​∇⋅F(x)dx=∮∂V​F⋅dS,

where the right-hand side is the outward flux of FFF through the six faces of VVV.

This is the divergence theorem invoked by the source to pass from the integral form of the continuity equation to its differential form.

Formalization Note The closed surface is the boundary of an axis-parallel box, as in Mathlib's divergence theorem; the flux is the sum over iii of the face integrals of FiF_iFi​ over xi=bix_i=b_ixi​=bi​ minus those over xi=aix_i=a_ixi​=ai​.

Preamble
import Mathlib
import Definitions.Def_ContinuityEqWiki_Defs
Formal statement
namespace ContinuityEqWiki

theorem integral_div_eq_boxFlux (F : Space → Space) (hF : ContDiff ℝ 1 F)
    (a b : Space) (hab : a ≤ b) :
    ∫ x in Set.Icc a b, div F x = boxFlux F a b := by sorry

end ContinuityEqWiki
Source
Wikipedia, "Continuity equation", revision oldid=1378634825, https://en.wikipedia.org/w/index.php?title=Continuity_equation&oldid=1378634825, section "Differential form" ("By the divergence theorem, a general continuity equation can also be written in a differential form")
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What the Lean code literally says, in plain math · Aristotle (Harmonic) - drafting agent, non-blind read-back

Non-blind read-back — not independent testimony. This read-back was written by the same agent (Aristotle, by Harmonic) that drafted the Lean statement it describes, at the explicit request of the proposal owner. Its author knew the source text and the intended meaning while writing it, so it must not be mistaken for a blind, independent audit. Reviewers should compare the Lean code against the source themselves.

For every vector field F:R3→R3F:\mathbb R^3\to\mathbb R^3F:R3→R3 that is continuously differentiable (C1C^1C1) on all of R3\mathbb R^3R3, and all a,b∈R3a,b\in\mathbb R^3a,b∈R3 with ai≤bia_i\le b_iai​≤bi​ for i=0,1,2i=0,1,2i=0,1,2 (degenerate boxes with some ai=bia_i=b_iai​=bi​ are allowed),

∫[a,b](∇⋅F)(x) dx=∑i=02(∫[a′,b′]Fi(ιi(bi,y)) dy−∫[a′,b′]Fi(ιi(ai,y)) dy),\int_{[a,b]}(\nabla\cdot F)(x)\,dx=\sum_{i=0}^{2}\left(\int_{[a',b']}F_i(\iota_i(b_i,y))\,dy-\int_{[a',b']}F_i(\iota_i(a_i,y))\,dy\right),∫[a,b]​(∇⋅F)(x)dx=i=0∑2​(∫[a′,b′]​Fi​(ιi​(bi​,y))dy−∫[a′,b′]​Fi​(ιi​(ai​,y))dy),

where ∇⋅F=∑i∂iFi\nabla\cdot F=\sum_i\partial_iF_i∇⋅F=∑i​∂i​Fi​ (partial derivatives as Fréchet derivatives along unit vectors), the left integral is the Lebesgue integral over the order box [a,b][a,b][a,b], a′,b′∈R2a',b'\in\mathbb R^2a′,b′∈R2 are a,ba,ba,b with coordinate iii removed, and ιi(s,y)\iota_i(s,y)ιi​(s,y) inserts sss as the iii-th coordinate of y∈R2y\in\mathbb R^2y∈R2.

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