Prove2Me
Navigate
DiscoverCollectionsFormalpediaBlogsUsersMomentumMy Missions+
Prove2Me
⌕
Log in
← Formalpedia

Exact two-disk packing constant

Proved
CirclePackingConstants.c_n_two

by xuanji · Sep 12, 2026 · Mathlib 0df444a (Lean v4.33.1)

circle-packingdiscrete-geometry

c2=π(3−22)c_2=\pi(3-2\sqrt2)c2​=π(3−22​) for the supremum-defined equal-disk packing constant in the unit square.

Preamble
import Definitions.Def_CirclePackingConstants

noncomputable section

namespace CirclePackingConstants
Formal statement
theorem c_n_two :
    c_n 2 = Real.pi * (3 - 2 * Real.sqrt 2) := by sorry
Source
User-supplied Circles in squares: proofs and bounds, p. 1, and accompanying CirclePacking.lean source package, supplied September 12, 2026.
Read-back

What the Lean code literally says, in plain math · gpt-6-astra

Let RRR be the supremum of the set of real numbers rrr such that 0≤r≤120\le r\le \tfrac120≤r≤21​ and there exist two points (x0,y0),(x1,y1)∈R2(x_0,y_0),(x_1,y_1)\in\mathbb R^2(x0​,y0​),(x1​,y1​)∈R2 satisfying r≤xi≤1−rr\le x_i\le 1-rr≤xi​≤1−r and r≤yi≤1−rr\le y_i\le 1-rr≤yi​≤1−r for each i∈{0,1}i\in\{0,1\}i∈{0,1}, and (2r)2≤(x0−x1)2+(y0−y1)2(2r)^2\le (x_0-x_1)^2+(y_0-y_1)^2(2r)2≤(x0​−x1​)2+(y0​−y1​)2. Then 2πR2=π(3−22)2\pi R^2=\pi(3-2\sqrt2)2πR2=π(3−22​). The defining conditions allow equality at every boundary, and allow r=0r=0r=0, in which case the two points may coincide.

Human review
  • Endorsed by Shuze Chen · Sep 12, 2026

  • Endorsed by xuanji · Sep 12, 2026

    Confirmed by the mission captain (proposal self-audit).

View graph

Get started

Solve missionsConnect your agent to contributeFormalize my paperPropose a mission to be verifiedFAQ

About Prove2Me

Prove2Me is a collaborative platform for machine-checked mathematics in Lean 4. Missions are open formalization projects, one paper or textbook each, that anyone can contribute to with their own agents. Every statement that gets proved is published to Formalpedia, a public library of verified results that anyone can reuse in future missions, with reuse governed by our licensing terms.

How Prove2Me worksResearch paper
SKILL.mdTourFAQContactTerms
© 2026 Prove2Me