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§4 — Fréchet spaces are quasi-complete

Proved
GarrettFA.isQuasiComplete_of_isFrechetSpace

by Lucas · Oct 12, 2026 · Mathlib 0df444a (Lean v4.33.1)

functional-analysistopological-vector-spaces

Every Fréchet space XXX over K=R\mathbb K=\mathbb RK=R or C\mathbb CC is quasi-complete:

X Freˊchet ⟹ every bounded Cauchy net in X converges.X \text{ Fréchet}\ \Longrightarrow\ \text{every bounded Cauchy net in } X \text{ converges}.X Freˊchet ⟹ every bounded Cauchy net in X converges.

In particular, Banach and Hilbert spaces are quasi-complete.

Preamble
import Definitions.Def_GarrettFA_IsQuasiComplete
import Definitions.Def_GarrettFA_IsFrechetSpace
Formal statement
namespace GarrettFA
theorem isQuasiComplete_of_isFrechetSpace {𝕜 : Type*} [RCLike 𝕜] {X : Type*} [AddCommGroup X] [Module 𝕜 X] [Module ℝ X]
    [IsScalarTower ℝ 𝕜 X] [UniformSpace X] [IsUniformAddGroup X] [ContinuousSMul 𝕜 X] [T2Space X]
    (hX : IsFrechetSpace 𝕜 X) :
    IsQuasiComplete 𝕜 X := by sorry
end GarrettFA
Source
Paul Garrett, *Completeness and quasi-completeness* (lecture notes, April 24, 2014), http://www.math.umn.edu/~garrett/m/fun/notes_2012-13/07d_quasi-completeness.pdf, p. 6, remark after Definition 4.0.2 ("Complete metric spaces are quasi-complete, so Hilbert, Banach, and Fréchet spaces are quasi-complete")
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What the Lean code literally says, in plain math · Aristotle (Harmonic)

Let K\mathbb KK be a real-or-complex scalar field (in practice R\mathbb RR or C\mathbb CC), and let XXX be a K\mathbb KK-vector space that is also a real vector space with compatible scalar multiplications, carrying a uniform structure for which addition and subtraction are uniformly continuous (so the uniformity is the canonical translation-invariant uniformity of the induced topology), with scalar multiplication K×X→X\mathbb K\times X\to XK×X→X jointly continuous, and Hausdorff. Assume XXX is Fréchet. Fréchet (the bundle's definition, applied to the given uniform structure): locally convex as a real topological vector space, the topology is metrizable, and the space is complete for its uniform structure (every Cauchy filter converges). Then XXX is quasi-complete over K\mathbb KK. Quasi-complete over K\mathbb KK (the bundle's definition): for every index type III (in the same universe as the space) carrying a partial order in which any two elements have a common upper bound, and every family (vi)i∈I(v_i)_{i\in I}(vi​)i∈I​ whose set of values is von Neumann bounded over K\mathbb KK and which is Cauchy (for every neighbourhood NNN of 000 there is i0i_0i0​ with vi−vj∈Nv_i-v_j\in Nvi​−vj​∈N for all i,j≥i0i,j\ge i_0i,j≥i0​), there is a point xxx with vi−x∈Nv_i-x\in Nvi​−x∈N eventually (for all i≥i\gei≥ some i0i_0i0​) for every neighbourhood NNN of 000.

Human review
  • Endorsed by Shuze Chen · Oct 13, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 13, 2026

    Confirmed by the mission captain (proposal self-audit).

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