Theorem 1.9 (Artin, 1925): which endomorphisms of are braid automorphisms
ProvedBraidsLinksMCG.thm_1_9_artin_characterizationTheorem 1.9 (Artin, 1925). Let be free of rank and let be an endomorphism of . Then belongs to — that is, is the automorphism induced by some braid under the Artin representation — if and only if
where is a permutation of and each is a word in the generators. In words: an endomorphism is a braid automorphism exactly when it permutes the generators up to conjugacy and fixes the product .
The representation is taken as a hypothesis: the statement is made for any homomorphism from to whose value on each is the endomorphism (1-14). Corollary 1.8.3 guarantees that at least one such exists, so the statement is not vacuous.
import Mathlib import Definitions.Def_BraidsLinksMCG_ArtinBraidGroup import Definitions.Def_BraidsLinksMCG_ArtinEndo
namespace BraidsLinksMCG
theorem thm_1_9_artin_characterization (n : ℕ)
(xi : ArtinBraidGroup n →* MulAut (FreeGroup (Fin n)))
(hxi : ∀ i : Fin (n - 1), ∀ w : FreeGroup (Fin n), xi (sigma i) w = artinEndo n i w)
(beta : FreeGroup (Fin n) →* FreeGroup (Fin n)) :
(∃ b : ArtinBraidGroup n, ∀ w : FreeGroup (Fin n), xi b w = beta w) ↔
((∃ mu : Equiv.Perm (Fin n), ∃ A : Fin n → FreeGroup (Fin n),
∀ i : Fin n, beta (FreeGroup.of i) = A i * FreeGroup.of (mu i) * (A i)⁻¹) ∧
beta (freeWordProd n) = freeWordProd n) := by sorry
end BraidsLinksMCG
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What the Lean code literally says, in plain math · self-authored-by-drafting-agent (non-blind)
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Fix a natural number , let be the free group on , and let be the presented group with generators and the braid relations.
Hypotheses. The statement is made for a given group homomorphism that satisfies, for every braid index and every , , where is Artin's endomorphism
and for a given group endomorphism (a homomorphism, not assumed bijective).
Conclusion. The following two statements are equivalent.
Left side. There exists such that and agree at every element of .
Right side. Both of the following hold:
- there exist a permutation of and a family of words such that for every ,
- fixes the ordered product of all generators:
Exact logical strength. The equivalence is stated for the given , which is a hypothesis of the statement rather than a constructed object: if no homomorphism with the displayed values on the generators existed, the statement would be vacuously true. The conjugators in (1) are arbitrary elements of and may depend on ; the permutation is arbitrary. Membership in the image of is expressed as pointwise agreement of functions on , not as equality of automorphisms in some quotient. No uniqueness of , or the is asserted.
Degenerate cases. is included: then is trivial and the equivalence reduces to a statement about the identity endomorphism of a free group of rank at most one.
Confirmed by the mission captain (proposal self-audit).