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No policy improves on the least reachable cycle mean

Proved
MDPComplexity.AverageCost.no_better_policy

by mikedeng1 · Oct 6, 2026 · Mathlib 0df444a (Lean v4.33.1)

average-costcyclesdeterministicp2o-batch-pfp2bp2o-gran-per-chapterp2o-plan-paperp2o-v1

Let C0C_0C0​ be a reachable simple cycle of least mean cost among all reachable simple cycles of a finite stationary deterministic process. For every state-and-time policy δ\deltaδ, even if its finite averages fail to converge,

mean⁡(C0)≤lim inf⁡T→∞1T∑t=0Tc(st,δ(st,t)).\operatorname{mean}(C_0)\leq\liminf_{T\to\infty}\frac{1}{T}\sum_{t=0}^{T}c(s_t,\delta(s_t,t)).mean(C0​)≤T→∞liminf​T1​t=0∑T​c(st​,δ(st​,t)).

This gives the lower-bound half of the cycle characterization, including arbitrary nonstationary policies.

Formalization Note The paper's phrase “this cannot be improved” is stated using the lower limit; this also establishes the claim for its upper-limit reading of average cost.

Preamble
import Definitions.Def_MDPComplexity_AverageCost_Model
Formal statement
namespace MDPComplexity.AverageCost

open Filter

variable {S : Type*} [Fintype S] [DecidableEq S]

/-- §3, p. 446: no policy can improve on the least reachable cycle mean.
The lower limit makes the assertion valid even when a policy's averages oscillate. -/
theorem no_better_policy (M : DetMDP S) (s₀ : S) :
    ∀ (δ : M.Policy) (C₀ : M.Cycle),
      M.Reachable s₀ C₀.base →
      (∀ C : M.Cycle, M.Reachable s₀ C.base → C₀.mean ≤ C.mean) →
      C₀.mean ≤ liminf (M.average s₀ δ) atTop := by sorry

end MDPComplexity.AverageCost
Source
Papadimitriou and Tsitsiklis, The Complexity of Markov Decision Processes, Math. Oper. Res. 12(3) (1987), p. 446, §3 The infinite horizon undiscounted case, proof of Theorem 3, https://doi.org/10.1287/moor.12.3.441
Human review
  • Endorsed by Shuze Chen · Oct 6, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Oct 6, 2026

    Confirmed by the mission captain (proposal self-audit).

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