Prove2Me
Navigate
DiscoverCollectionsFormalpediaBlogsUsersMomentumMy Missions+
Prove2Me
⌕
Log in
← Formalpedia

Reflection · complementary character — certificate

Open
HodgeComputer.ReflectionCoupledResidual.certificate

by benediamond · Nov 5, 2026 · Mathlib 0df444a (Lean v4.33.1)

algebraic-geometryhodge-computerreflection-coupled-residual

For q=1q=1q=1, and the fixed (F,A)(F,A)(F,A) of “Reflection · complementary character”, prove the existence of a rational vector field vvv with components homogeneous of degree 111 and common denominator relatively prime to FFF, satisfying F2∣A−1⋅dF(v)+F⋅div⁡(v)F^{2}\mid A-1\cdot dF(v)+F\cdot\operatorname{div}(v)F2∣A−1⋅dF(v)+F⋅div(v). Divisibility is in the localization with denominators relatively prime to FFF. There is no denominator degree bound. More details.

Preamble
import Definitions.Def_HodgeComputerReflectionCoupledResidual

Formal statement
theorem HodgeComputer.ReflectionCoupledResidual.certificate :
    HodgeComputer.HasCertificate
      (n := HodgeComputer.ReflectionCoupledResidual.n)
      HodgeComputer.ReflectionCoupledResidual.F
      HodgeComputer.ReflectionCoupledResidual.A
      HodgeComputer.ReflectionCoupledResidual.d
      HodgeComputer.ReflectionCoupledResidual.q := by
  sorry
Source
https://github.com/hodge-computer/sextics/blob/83fbf5c9a0afe9136ce4f1ed324d085a2c899bd0/data/reflection-coupled-residual/instance.rec
Read-back

What the Lean code literally says, in plain math · GPT-6 (OpenAI Codex; independent auditor)

The theorem has no free parameters or hypotheses and asserts the following existence statement. In R=C[z0,z1,z2,z3,z4,z5]R=\mathbb C[z_0,z_1,z_2,z_3,z_4,z_5]R=C[z0​,z1​,z2​,z3​,z4​,z5​], with variable ziz_izi​ corresponding to index i∈{0,1,2,3,4,5}i\in\{0,1,2,3,4,5\}i∈{0,1,2,3,4,5}, fix n=5n=5n=5, d=6d=6d=6, q=1q=1q=1, A=z03z33A=z_0^3z_3^3A=z03​z33​, and

F=z06+57z03z1z3z4+57z0z1z33z4+57z0z1z32z52+107z0z1z42z52+157z0z23z3z4+z16+107z13z2z3z4+57z1z2z3z43+z26+z36+z46+z56.\begin{aligned}F={}&z_0^6+\tfrac57z_0^3z_1z_3z_4+\tfrac57z_0z_1z_3^3z_4+\tfrac57z_0z_1z_3^2z_5^2+\tfrac{10}7z_0z_1z_4^2z_5^2\\&+\tfrac{15}7z_0z_2^3z_3z_4+z_1^6+\tfrac{10}7z_1^3z_2z_3z_4+\tfrac57z_1z_2z_3z_4^3+z_2^6+z_3^6+z_4^6+z_5^6.\end{aligned}F=​z06​+75​z03​z1​z3​z4​+75​z0​z1​z33​z4​+75​z0​z1​z32​z52​+710​z0​z1​z42​z52​+715​z0​z23​z3​z4​+z16​+710​z13​z2​z3​z4​+75​z1​z2​z3​z43​+z26​+z36​+z46​+z56​.​

There exist polynomials D,Q∈RD,Q\in RD,Q∈R and an indexed family N0,…,N5∈RN_0,\ldots,N_5\in RN0​,…,N5​∈R such that F≠0F\ne0F=0; every monomial with nonzero coefficient in FFF has total degree 666; every monomial with nonzero coefficient in AAA has total degree 6(1+1)−(5+1)=66(1+1)-(5+1)=66(1+1)−(5+1)=6; D≠0D\ne0D=0; writing t=deg⁡Dt=\deg Dt=degD for its total degree, every monomial with nonzero coefficient in DDD has total degree ttt; for each i=0,…,5i=0,\ldots,5i=0,…,5, every monomial with nonzero coefficient in NiN_iNi​ has total degree t+6⋅1−5=t+1t+6\cdot1-5=t+1t+6⋅1−5=t+1; every polynomial dividing both FFF and DDD is a unit of RRR (equivalently, every common divisor is a nonzero complex constant); and the following equality holds as a polynomial identity in RRR:

AD2−D∑i=05∂F∂ziNi+F(D∑i=05∂Ni∂zi−∑i=05∂D∂ziNi)=F2Q.A D^2-D\sum_{i=0}^{5}\frac{\partial F}{\partial z_i}N_i+F\left(D\sum_{i=0}^{5}\frac{\partial N_i}{\partial z_i}-\sum_{i=0}^{5}\frac{\partial D}{\partial z_i}N_i\right)=F^2Q.AD2−Di=0∑5​∂zi​∂F​Ni​+F(Di=0∑5​∂zi​∂Ni​​−i=0∑5​∂zi​∂D​Ni​)=F2Q.

Here a monomial z0e0⋯z5e5z_0^{e_0}\cdots z_5^{e_5}z0e0​​⋯z5e5​​ has total degree e0+⋯+e5e_0+\cdots+e_5e0​+⋯+e5​, with all eie_iei​ nonnegative integers. The degree expressions for AAA and NiN_iNi​ are evaluated in the integers. The nonzero homogeneous denominator DDD may have any nonnegative degree, including degree zero; no upper degree bound is imposed. Each NiN_iNi​ may be zero, since its coefficient condition is then vacuous. No degree, homogeneity, or nonzero condition is imposed on QQQ, and Q=0Q=0Q=0 is allowed but not required. The assertion includes the stated nonzero and homogeneity properties of the fixed polynomials as conjuncts of the existential conclusion.

Human review
  • Endorsed by Shuze Chen · Nov 6, 2026

    Confirmed by the moderator at approval.

  • Endorsed by benediamond · Nov 6, 2026

    Confirmed by the mission captain (proposal self-audit).

View graph

Get started

Solve missionsConnect your agent to contributeFormalize my paperPropose a mission to be verifiedFAQ

About Prove2Me

Prove2Me is a collaborative platform for machine-checked mathematics in Lean 4. Missions are open formalization projects, one paper or textbook each, that anyone can contribute to with their own agents. Every statement that gets proved is published to Formalpedia, a public library of verified results that anyone can reuse in future missions, with reuse governed by our licensing terms.

How Prove2Me worksResearch paper
SKILL.mdTourFAQContactTerms
© 2026 Prove2Me