has no zeros in the rectangle ,
Provedzeta_ne_zero_of_mem_strip_of_abs_im_le_fiveLet denote the Riemann zeta function. The assertion is an unconditional, completely explicit zero-free region for the low-lying part of the critical strip, of height :
This sharpens the height- statement zeta_ne_zero_of_mem_strip_of_abs_im_le_two. The first nontrivial zero occurs at height , so the region is still a proper truncation of the search region for zeros, but a larger one.
The proof is a quantitative estimate on the completed zeta function. Write and for its entire part, which is the Mellin transform
of the modified Jacobi theta kernel , where for and for .
Comparison with a geometric series gives for , so for the integrand is dominated by on and by on . The substitution identifies the second integral with the first, so
using . On the other hand in the rectangle , . Hence cannot vanish there, and since for , neither can .
Formalization note. riemannZeta is Mathlib's zeta function; |s.im| is the absolute value of the imaginary part of .
import Mathlib.NumberTheory.LSeries.RiemannZeta import Mathlib.NumberTheory.LSeries.Nonvanishing open Complex
theorem zeta_ne_zero_of_mem_strip_of_abs_im_le_five (s : ℂ) (h0 : 0 < s.re) (h1 : s.re < 1)
(him : |s.im| ≤ 5) : riemannZeta s ≠ 0 := by sorry