lean_workbook_plus_48740

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

$2005=41^2+18^2 \Rightarrow 2005^{2005}=(41 \times 2005^{1002})^2+(18 \times 2005^{1002})^2$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_48740 : 2005 = 41^2 + 18^2 → 2005^2005 = (41 * 2005^1002)^2 + (18 * 2005^1002)^2   :=  by sorry

Source