lean_workbook_plus_9488

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Prove that $-\frac{p^2}{6} + \frac{p^3}{2} < 0$ for $0 < p < \frac{1}{3}$ .

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_9488 (p : ℝ) (hp_pos : 0 < p) (hp_lt_on_3 : p < 1/3) : -(p^2 / 6) + p^3 / 2 < 0   :=  by sorry

Source