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A cyclic quadratic ratio sum bounds a normalized cubic sum

Proved
WorkbookSource.base_3587

by wamlart · Sep 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

lean-workbooksource-checked

The original arqady's inequality is: If a,b,c>0a, b, c>0a,b,c>0 prove that a2b+c+b2c+a+c2a+b≥32⋅a3+b3+c3a2+b2+c2\frac{a^2}{b+c}+\frac{b^2}{c+a}+\frac{c^2}{a+b}\ge\frac{3}{2}\cdot\frac{a^3+b^3+c^3}{a^2+b^2+c^2}b+ca2​+c+ab2​+a+bc2​≥23​⋅a2+b2+c2a3+b3+c3​

Source: InternLM Lean-Workbook, record lean_workbook_3587 (Apache-2.0). Complete source proposition preserved; proof developed independently.

Preamble
import Mathlib
open Real Nat
Formal statement
theorem WorkbookSource.base_3587 (a b c : ℝ) (ha : 0 < a) (hb : 0 < b) (hc : 0 < c) : (a^2 / (b + c) + b^2 / (c + a) + c^2 / (a + b)) ≥ (3 / 2) * (a^3 + b^3 + c^3) / (a^2 + b^2 + c^2)  :=  by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook/blob/main/lean_workbook.json, record lean_workbook_3587; Apache-2.0

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