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Directional bounds on a denominator change lift to crossIntegral

Proved
RybinAI2026.P01.crossIntegral_le_of_rankOne_le

by Steve1136 · Sep 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

integral-inequalitymatrix-analysispositive-definite-matrices

Let AAA and DDD be real symmetric positive-definite n×nn\times nn×n matrices, let σ\sigmaσ be the mission's unnormalised surface measure on the unit sphere S⊂RnS\subset\mathbb R^nS⊂Rn, and let ρ∈R\rho\in\mathbb Rρ∈R. Suppose that for every vector w∈Rnw\in\mathbb R^nw∈Rn

∫S∣⟨u,w⟩∣uTDu dσ(u)  ≤  ρ∫S∣⟨u,w⟩∣uTAu dσ(u).\int_S\frac{|\langle u,w\rangle|}{u^{\mathsf T}Du}\,d\sigma(u)\;\le\;\rho\int_S\frac{|\langle u,w\rangle|}{u^{\mathsf T}Au}\,d\sigma(u).∫S​uTDu∣⟨u,w⟩∣​dσ(u)≤ρ∫S​uTAu∣⟨u,w⟩∣​dσ(u).

Then for all real matrices X,YX,YX,Y and every positive-definite PPP, the mixed spherical integral KKK (crossIntegral) satisfies

K(X,Y,D,P)≤ρ K(X,Y,A,P)andK(X,Y,P,D)≤ρ K(X,Y,P,A).K(X,Y,D,P)\le\rho\,K(X,Y,A,P)\qquad\text{and}\qquad K(X,Y,P,D)\le\rho\,K(X,Y,P,A).K(X,Y,D,P)≤ρK(X,Y,A,P)andK(X,Y,P,D)≤ρK(X,Y,P,A).

Why it is true. Put M=X−YM=X-YM=X−Y. In the first slot, Fubini gives

K(X,Y,D,P)=∫S1vTPv∫S∣⟨u,Mv⟩∣uTDu dσ(u) dσ(v).K(X,Y,D,P)=\int_S\frac{1}{v^{\mathsf T}Pv}\int_S\frac{|\langle u,Mv\rangle|}{u^{\mathsf T}Du}\,d\sigma(u)\,d\sigma(v).K(X,Y,D,P)=∫S​vTPv1​∫S​uTDu∣⟨u,Mv⟩∣​dσ(u)dσ(v).

Applying the hypothesis with w=Mvw=Mvw=Mv bounds the inner integral, and the weight 1/(vTPv)1/(v^{\mathsf T}Pv)1/(vTPv) is positive. In the second slot, ∣uTMv∣=∣⟨v,MTu⟩∣|u^{\mathsf T}Mv|=|\langle v,M^{\mathsf T}u\rangle|∣uTMv∣=∣⟨v,MTu⟩∣, so apply the hypothesis to the inner vvv-integral with w=MTuw=M^{\mathsf T}uw=MTu. All integrands are continuous on the compact sphere (or its square) because the denominators are strictly positive there, so every integral is finite and Fubini applies. In dimension 000 the sphere is empty and all integrals vanish.

This is the infrastructure step saying that a directional (rank-one numerator) bound on a denominator change lifts to the full mixed double integral in either slot. Lean writes ⟨u,w⟩\langle u,w\rangle⟨u,w⟩ as bilinear 1 u w.

Preamble
import Definitions.Def_rybin2026_p01_cross_integral

set_option autoImplicit false

open Matrix MeasureTheory RybinAI2026.P01
Formal statement
theorem RybinAI2026.P01.crossIntegral_le_of_rankOne_le
    {n : ℕ} (A D : Matrix (Fin n) (Fin n) ℝ)
    (hA : A.PosDef) (hD : D.PosDef) (ρ : ℝ)
    (h : ∀ w : Euclidean n,
      ∫ u, |bilinear (1 : Matrix (Fin n) (Fin n) ℝ) u.1 w| / bilinear D u.1 u.1
          ∂surfaceMeasure n ≤
        ρ * ∫ u, |bilinear (1 : Matrix (Fin n) (Fin n) ℝ) u.1 w| / bilinear A u.1 u.1
          ∂surfaceMeasure n) :
    ∀ (X Y P : Matrix (Fin n) (Fin n) ℝ), P.PosDef →
      crossIntegral X Y D P ≤ ρ * crossIntegral X Y A P ∧
      crossIntegral X Y P D ≤ ρ * crossIntegral X Y P A := by
  sorry
Source
Reformulation of Prove2Me theorem RybinAI2026.P01.crossIntegral_add_double_l1_coefficients (mission: Positive definite matrix integral inequality; original problem https://rybindmitry.github.io/problems/1.html)

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