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Tree Extension Lemma for every two-letter prefix (at most one helper)

Proved
Erdos195.two_letter_tree_extension

by Ethan Cheung Wang · Oct 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

arithmetic-progressionscombinatoricserdos-problems

A tree witness is a function θ(k,r)∈{0,1}\theta(k,r)\in\{0,1\}θ(k,r)∈{0,1} on the nodes (k,r)(k,r)(k,r), 0≤r<2k0\le r<2^k0≤r<2k, of the binary tree of residues. For distinct integers x,yx,yx,y with k=ν2(y−x)k=\nu_2(y-x)k=ν2​(y−x), put x≺θyx\prec_\theta yx≺θ​y iff bitk(x)=θ(k, x mod 2k)\mathrm{bit}_k(x)=\theta(k,\,x\bmod 2^k)bitk​(x)=θ(k,xmod2k) (two's-complement digits). A finite word QQQ of integers is θ\thetaθ-safe if the sequence "the letters of QQQ in order, then all remaining integers in ≺θ\prec_\theta≺θ​-order" contains no monotone 444-term arithmetic progression. Let a,b,ta,b,ta,b,t be pairwise distinct integers, k=ν2(b−a)k=\nu_2(b-a)k=ν2​(b−a), ℓ=ν2(t−b)\ell=\nu_2(t-b)ℓ=ν2​(t−b). Then for some tree witness θ\thetaθ the word

(a,b,t)  if k≠ℓ,(a,b, 2t−b, t)  if k=ℓ(a,b,t)\ \text{ if } k\neq\ell,\qquad (a,b,\,2t-b,\,t)\ \text{ if } k=\ell(a,b,t)  if k=ℓ,(a,b,2t−b,t)  if k=ℓ

is θ\thetaθ-safe. This is the Tree Extension Lemma for all two-letter prefixes, with at most one helper letter; it includes the case (0,u)(0,u)(0,u), u≡3u\equiv3u≡3, t≡2(mod4)t\equiv2\pmod 4t≡2(mod4) that needs at least two helpers for ε\varepsilonε-orders.

Formalization note: treeLt θ is from Definitions.Def_Erdos195_tree; Safe, bitOne, No3AP, Star, HasMonotoneAP are from Definitions.Def_Erdos195_defs. Positions in a word are List.idxOf; ν2\nu_2ν2​ is padicValInt 2.

Preamble
import Mathlib
import Definitions.Def_Erdos195_tree
Formal statement
namespace Erdos195

theorem two_letter_tree_extension (a b t : ℤ) (hab : a ≠ b) (hat : a ≠ t) (hbt : b ≠ t) :
    ∃ θ : ℕ → ℤ → Bool, Safe (treeLt θ)
      (if padicValInt 2 (b - a) = padicValInt 2 (t - b) then [a, b, 2 * t - b, t]
        else [a, b, t]) := by sorry

end Erdos195
Source
Erdős Problem 195 (https://www.erdosproblems.com/195); tree-witness framework and statement from GPT 6 Astra (Oct 23 2026 answers), Lean-verified by Grok Bot for Ethan Cheung

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