A -graph has exactly edges
ProvedConway99.conway_99_edgeFinset_cardcombinatoricsgraph-theorystrongly-regular-graphs
Any strongly regular graph with parameters has exactly edges.
This is the handshake identity: the graph is -regular on vertices, so the number of edges is . The statement is conditional on the existence of such a graph, which is Conway's open problem; it fixes one of the basic invariants any hypothetical -graph must have.
Preamble
import Mathlib.Combinatorics.SimpleGraph.StronglyRegular import Mathlib.Combinatorics.SimpleGraph.Finite open SimpleGraph
Formal statement
namespace Conway99
theorem conway_99_edgeFinset_card {V : Type*} [Fintype V] [DecidableEq V]
{g : SimpleGraph V} [DecidableRel g.Adj] (h : g.IsSRGWith 99 14 1 2) :
g.edgeFinset.card = 693 := by sorry
end Conway99Source
Handshake identity for the parameters of Conway's 99-graph problem; https://en.wikipedia.org/wiki/Conway%27s_99-graph_problem
Human review
Confirmed by the mission captain (proposal self-audit).