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Arithmetic_Mean_is_Never_Less_than_Harmonic_Mean

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

am-hmanalysisinequalityproofwiki

Let x1,x2,…,xn∈R>0x_1, x_2, \ldots, x_n \in \R_{> 0}x1​,x2​,…,xn​∈R>0​ be strictly positive real numbers. Let AnA_n An​ be the arithmetic mean of x1,x2,…,xnx_1, x_2, \ldots, x_nx1​,x2​,…,xn​. Let HnH_nHn​ be the harmonic mean of x1,x2,…,xnx_1, x_2, \ldots, x_nx1​,x2​,…,xn​. Then An≥HnA_n \ge H_nAn​≥Hn​.

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem Arithmetic_Mean_is_Never_Less_than_Harmonic_Mean (n : ℕ) (hn : 0 < n) (x : Fin n → ℝ) (hx : ∀ i, 0 < x i) : n / (∑ i : Fin n, (x i)⁻¹) ≤ (∑ i : Fin n, x i) / n := by sorry
Source
https://proofwiki.org/wiki/Arithmetic_Mean_is_Never_Less_than_Harmonic_Mean

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