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If a space of dimension ≤ 5 containing 1, u, 1/u carries a 2×3 configuration x ⊗ y with x₁/x₀ = p(u)/q(u) in lowest terms, then deg p, deg q ≤ 2

Proved
DiazModulus.two_by_three_configuration_ratio_degree_le_two

by carlok · Oct 18, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Let u∈C∖Q‾u \in \mathbb{C} \setminus \overline{\mathbb{Q}}u∈C∖Q​ and let W⊆CW \subseteq \mathbb{C}W⊆C be a finite-dimensional Q‾\overline{\mathbb{Q}}Q​-subspace with dim⁡W≤5\dim W \leq 5dimW≤5 and 1,u,u−1∈W1, u, u^{-1} \in W1,u,u−1∈W. Let x0,x1x_0, x_1x0​,x1​ be linearly independent over Q‾\overline{\mathbb{Q}}Q​, and y0,y1,y2y_0, y_1, y_2y0​,y1​,y2​ too, with xiyj∈Wx_iy_j \in Wxi​yj​∈W for all i,ji, ji,j, and let p,q∈Q‾[X]p, q \in \overline{\mathbb{Q}}[X]p,q∈Q​[X] be coprime with max⁡(deg⁡p,deg⁡q)≥1\max(\deg p, \deg q) \geq 1max(degp,degq)≥1 and x1q(u)=x0p(u)x_1q(u) = x_0p(u)x1​q(u)=x0​p(u). Then max⁡(deg⁡p,deg⁡q)≤2\max(\deg p, \deg q) \leq 2max(degp,degq)≤2.

Proof. Coprimality and max⁡(deg⁡p,deg⁡q)≥1\max(\deg p, \deg q) \geq 1max(degp,degq)≥1 give q(u)≠0q(u) \neq 0q(u)=0, so x1=x0hx_1 = x_0hx1​=x0​h with h=p(u)/q(u)h = p(u)/q(u)h=p(u)/q(u); as xxx is free, h∉Q‾h \notin \overline{\mathbb{Q}}h∈/Q​, so hhh is transcendental over Q‾\overline{\mathbb{Q}}Q​. Put Y′=span(x0y0,x0y1,x0y2)Y' = \mathrm{span}(x_0y_0, x_0y_1, x_0y_2)Y′=span(x0​y0​,x0​y1​,x0​y2​) and XY=Y′+hY′⊆WXY = Y' + hY' \subseteq WXY=Y′+hY′⊆W, the span of the six products, so that dim⁡(Y′∩hY′)≥1\dim(Y' \cap hY') \geq 1dim(Y′∩hY′)≥1. If H=span(1,u,u−1)⊆XYH = \mathrm{span}(1, u, u^{-1}) \subseteq XYH=span(1,u,u−1)⊆XY, a non-zero ht∈Y′∩hY′ht \in Y' \cap hY'ht∈Y′∩hY′ with t∈Y′t \in Y't∈Y′ and some c′∈Y′c' \in Y'c′∈Y′ outside span(t,ht)\mathrm{span}(t, ht)span(t,ht) give XY⊆span(t,th,th2,tk,thk)XY \subseteq \mathrm{span}(t, th, th^2, tk, thk)XY⊆span(t,th,th2,tk,thk) with k=c′/tk = c'/tk=c′/t, and DiazModulus.progression_pair_span_ratio_degree_le_two applies. Otherwise dim⁡XY≤4\dim XY \leq 4dimXY≤4, so two planes in Y′Y'Y′ meet and give t,th,th2∈Y′t, th, th^2 \in Y't,th,th2∈Y′; then XY=span(t,th,th2,th3)XY = \mathrm{span}(t, th, th^2, th^3)XY=span(t,th,th2,th3), the span of HHH and XYXYXY has dimension 555, and DiazModulus.progression_space_ratio_degree_le_two applies.

Novelty. Not found in the sources read; routine. When the six products span four dimensions, the step to a progression t,th,th2,th3t, th, th^2, th^3t,th,th2,th3 is that of Bachoc, Serra and Zémor (2017, Lemma 4).

Preamble
import Definitions.Def_DiazModulus
Formal statement
open Complex ComplexConjugate

namespace DiazModulus

open Polynomial in
theorem two_by_three_configuration_ratio_degree_le_two (u : ℂ) (hu : u ∉ Qbar) (W : Submodule (↥Qbar) ℂ)
    [FiniteDimensional (↥Qbar) W] (hW : Module.finrank (↥Qbar) W ≤ 5)
    (h1 : (1 : ℂ) ∈ W) (hu1 : u ∈ W) (hui : u⁻¹ ∈ W)
    (x : Fin 2 → ℂ) (y : Fin 3 → ℂ) (hx : LinearIndependent (↥Qbar) x)
    (hy : LinearIndependent (↥Qbar) y) (hxy : ∀ i j, x i * y j ∈ W)
    (p q : (↥Qbar)[X]) (hcop : IsCoprime p q) (hdeg : 1 ≤ max p.natDegree q.natDegree)
    (hpq : x 1 * aeval u q = x 0 * aeval u p) :
    max p.natDegree q.natDegree ≤ 2 := by
  sorry

end DiazModulus
Source
Not found in the sources read; when the products span four dimensions, the progression is that of C. Bachoc, O. Serra, G. Zémor, An analogue of Vosper's theorem for extension fields, Math. Proc. Cambridge Philos. Soc. (2017), Lemma 4. Uses DiazModulus.progression_space_ratio_degree_le_two and DiazModulus.progression_pair_span_ratio_degree_le_two. R18 of the Diaz modulus mission. Formal proof: Diaz modulus mission, 18 October 2026 (C. Perassi).

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