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Exact membership in the recursive radix representation family

Proved
ThreeSum.Radix.mem_representations

by wurtle · Oct 14, 2026 · Mathlib 0df444a (Lean v4.33.1)

3sumalgorithmsfine-grained-complexitythree-sum-1962word-ram

Let Ω\OmegaΩ be a finite type with decidable equality, let p∈Z∖{0}p\in\mathbb Z\setminus\{0\}p∈Z∖{0}, and let ℓ,r:Ω→Z\ell,r:\Omega\to\mathbb Zℓ,r:Ω→Z be endpoint maps. For a list x=(x0,…,xs−1)x=(x_0,\ldots,x_{s-1})x=(x0​,…,xs−1​), define the low-digit-first positional hash Hu(x)=∑i<spiu(xi)H_u(x)=\sum_{i<s}p^i u(x_i)Hu​(x)=∑i<s​piu(xi​).

The recursive family Rj(a,b)R_j(a,b)Rj​(a,b) chooses a first symbol whose two endpoint differences are divisible by ppp, then recurses on the quotient targets; R0(a,b)={[]}R_0(a,b)=\{[]\}R0​(a,b)={[]}. For all natural jjj, integer targets a,ba,ba,b, and lists xxx,

x∈Rj(a,b)  ⟺  ∣x∣=j ∧ pj∣a−Hℓ(x) ∧ pj∣b−Hr(x).x\in R_j(a,b)\iff |x|=j\ \land\ p^j\mid a-H_\ell(x)\ \land\ p^j\mid b-H_r(x).x∈Rj​(a,b)⟺∣x∣=j ∧ pj∣a−Hℓ​(x) ∧ pj∣b−Hr​(x).

This identifies the recursive candidate family with exactly the simultaneous positional congruences, including the original local choices.

Preamble
import Aesop
import Definitions.Def_ThreeSum1962Source_Bundle01
import Lean.Elab.Tactic.Omega
import Mathlib.Algebra.Order.BigOperators.Group.Finset
import Mathlib.Data.Finset.Card
import Mathlib.Data.Int.ModEq
import Mathlib.Tactic.Linarith
import Mathlib.Tactic.Ring
import Mathlib.Tactic.SplitIfs
import Theorems.Thm_ThreeSum_Radix_radix_divisibility


set_option autoImplicit false
set_option relaxedAutoImplicit false
set_option Elab.async false

universe u_1
Formal statement
theorem ThreeSum.Radix.mem_representations : ∀ {Ω : Type u_1} [inst : Fintype.{u_1} Ω] [inst_1 : DecidableEq.{u_1 + 1} Ω] (p : Int)
  (hp : @Ne.{1} Int p (@OfNat.ofNat.{0} Int (nat_lit 0) (@instOfNat (nat_lit 0)))) (left right : Ω → Int) (j : Nat)
  (a b : Int) (xs : List.{u_1} Ω),
  Iff
    (@Membership.mem.{u_1, u_1} (List.{u_1} Ω) (Finset.{u_1} (List.{u_1} Ω))
      (@SetLike.instMembership.{u_1, u_1} (Finset.{u_1} (List.{u_1} Ω)) (List.{u_1} Ω)
        (@Finset.instSetLike.{u_1} (List.{u_1} Ω)))
      (@ThreeSum.Radix.representations.{u_1} Ω inst inst_1 p left right j a b) xs)
    (And (@Eq.{1} Nat (@List.length.{u_1} Ω xs) j)
      (And
        (@Dvd.dvd.{0} Int Int.instDvd
          (@HPow.hPow.{0, 0, 0} Int Nat Int
            (@instHPow.{0, 0} Int Nat (@NPow.toPow.{0} Int (@Monoid.toNPow.{0} Int Int.instMonoid))) p j)
          (@HSub.hSub.{0, 0, 0} Int Int Int (@instHSub.{0} Int Int.instSub) a
            (@ThreeSum.Radix.positionalHash.{u_1} Ω p left xs)))
        (@Dvd.dvd.{0} Int Int.instDvd
          (@HPow.hPow.{0, 0, 0} Int Nat Int
            (@instHPow.{0, 0} Int Nat (@NPow.toPow.{0} Int (@Monoid.toNPow.{0} Int Int.instMonoid))) p j)
          (@HSub.hSub.{0, 0, 0} Int Int Int (@instHSub.{0} Int Int.instSub) b
            (@ThreeSum.Radix.positionalHash.{u_1} Ω p right xs))))) := by
  sorry
Source
https://github.com/c0ldzy17/three-sum-lean/blob/2b639655e07421b9ac743de9090459bab473a7c0/Submission/ThreeSum/Radix.lean#L66-L87

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