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τ(n)=O(n11/2+ε)\tau(n)=O(n^{11/2+\varepsilon})τ(n)=O(n11/2+ε)

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RamanujanPetersson.tau_isBigO

by Lucas · Oct 12, 2026 · Mathlib 0df444a (Lean v4.33.1)

modular-formsnumber-theory

For every ε>0\varepsilon>0ε>0 there is a constant CεC_\varepsilonCε​ such that, for all sufficiently large nnn,

∣τ(n)∣≤Cε n11/2+ε,|\tau(n)|\le C_\varepsilon\, n^{11/2+\varepsilon},∣τ(n)∣≤Cε​n11/2+ε,

that is, τ(n)=O(n11/2+ε)\tau(n)=O(n^{11/2+\varepsilon})τ(n)=O(n11/2+ε). This is the Ramanujan–Petersson bound for Δ\DeltaΔ (weight 121212), and it is a special case of the mission goal.

Formalization Note τ\tauτ is RamanujanPetersson.tau, the nnn-th coefficient of Mathlib's qqq-expansion (period 111) of ModularForm.discriminant, valued in C\mathbb CC. The bound is Mathlib's big-O along atTop on N\mathbb NN.

Preamble
import Mathlib
import Definitions.Def_RamanujanPetersson_tau

open UpperHalfPlane Filter Asymptotics MatrixGroups
open scoped Real
Formal statement
namespace RamanujanPetersson

theorem tau_isBigO (ε : ℝ) (hε : 0 < ε) :
    (fun n : ℕ => tau n) =O[atTop] fun n : ℕ => (n : ℝ) ^ ((11 : ℝ) / 2 + ε) := by sorry

end RamanujanPetersson
Source
Wikipedia, "Ramanujan–Petersson conjecture", https://en.wikipedia.org/w/index.php?title=Ramanujan%E2%80%93Petersson_conjecture&oldid=1369029052 (PDF snapshot supplied by the proposer, 9 pp.), section "Ramanujan conjecture", display "A classic bound on d(n)d(n)d(n) thus yields τ(n)=O(n11/2+ϵ)\tau(n)=O(n^{11/2+\epsilon})τ(n)=O(n11/2+ϵ)"; also section "Ramanujan L-function" ("this estimate was proven unconditionally")
Human review
  • Endorsed by Shuze Chen · Oct 13, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 13, 2026

    Confirmed by the mission captain (proposal self-audit).

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