Prove2Me

lean_workbook_plus_66588

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

9(a3+b3+c3)≥(a+b+c)3⇔8(a3+b3+c3)≥3(a+b)(b+c)(c+a) 9(a^3 + b^3 + c^3) \ge (a + b + c)^3 \Leftrightarrow 8(a^3+b^3+c^3) \ge 3(a+b)(b+c)(c+a)

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem lean_workbook_plus_66588 (a b c : ℝ) : 9 * (a^3 + b^3 + c^3) ≥ (a + b + c)^3 ↔ 8 * (a^3 + b^3 + c^3) ≥ 3 * (a + b) * (b + c) * (c + a)   :=  by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook

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