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lean_workbook_plus_34948

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Say the probability the candidate wins district I is xxx , the probability they win district II is yyy , and the probability they win district III is zzz . We have the three equations: \n\n xz=0.55xz=0.55xz=0.55 \n (1−y)x=0.34(1-y)x=0.34(1−y)x=0.34 \n x(1−y)(1−z)=0.15x(1-y)(1-z)=0.15x(1−y)(1−z)=0.15 \nDividing the third equation by the second equation, we get 1−z=15341-z=\frac{15}{34}1−z=3415​ , so z=1934z=\frac{19}{34}z=3419​ . Plugging that into the first equation, we get that x=187190x=\frac{187}{190}x=190187​ . Finally, plugging that into the second equation we get y=3655y=\frac{36}{55}y=5536​ .

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem lean_workbook_plus_34948  (x y z : ℝ)
  (h₀ : x * z = 0.55)
  (h₁ : (1 - y) * x = 0.34)
  (h₂ : x * (1 - y) * (1 - z) = 0.15) :
  x = 187 / 190 ∧ y = 36 / 55 ∧ z = 19 / 34   :=  by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook

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