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Exact finite characterization of θ\thetaθ-safety for tree orders

Proved
Erdos195.treeLt_safe_iff

by Ethan Cheung Wang · Oct 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

arithmetic-progressionscombinatoricserdos-problems

A tree witness is a function θ(k,r)∈{0,1}\theta(k,r)\in\{0,1\}θ(k,r)∈{0,1} on the nodes (k,r)(k,r)(k,r), 0≤r<2k0\le r<2^k0≤r<2k, of the binary tree of residues. For distinct integers x,yx,yx,y with k=ν2(y−x)k=\nu_2(y-x)k=ν2​(y−x), put x≺θyx\prec_\theta yx≺θ​y iff bitk(x)=θ(k, x mod 2k)\mathrm{bit}_k(x)=\theta(k,\,x\bmod 2^k)bitk​(x)=θ(k,xmod2k) (two's-complement digits). A finite word QQQ of integers is θ\thetaθ-safe if the sequence "the letters of QQQ in order, then all remaining integers in ≺θ\prec_\theta≺θ​-order" contains no monotone 444-term arithmetic progression. Call aaa before bbb in QQQ an open pair if neither 2b−a2b-a2b−a nor 3b−2a3b-2a3b−2a lies in QQQ. Then QQQ is θ\thetaθ-safe if and only if

(1) every in-order 3-AP a,b,2b−a of Q has 3b−2a∈Q placed before 2b−a,(2) every open pair (a,b) has θ(k, a mod 2k)=bitk(b), k=ν2(b−a).\text{(1) every in-order 3-AP } a,b,2b-a \text{ of } Q \text{ has } 3b-2a\in Q \text{ placed before } 2b-a,\qquad \text{(2) every open pair } (a,b) \text{ has } \theta\bigl(k,\,a\bmod 2^k\bigr)=\mathrm{bit}_k(b),\ k=\nu_2(b-a).(1) every in-order 3-AP a,b,2b−a of Q has 3b−2a∈Q placed before 2b−a,(2) every open pair (a,b) has θ(k,amod2k)=bitk​(b), k=ν2​(b−a).

This is the exact finite characterization of safety for tree orders (the tree analogue of condition (C)).

Formalization note: treeLt θ is from Definitions.Def_Erdos195_tree; Safe, bitOne, No3AP, Star, HasMonotoneAP are from Definitions.Def_Erdos195_defs. Positions in a word are List.idxOf; ν2\nu_2ν2​ is padicValInt 2.

Preamble
import Mathlib
import Definitions.Def_Erdos195_tree
Formal statement
namespace Erdos195

theorem treeLt_safe_iff (θ : ℕ → ℤ → Bool) (Q : List ℤ) :
    Safe (treeLt θ) Q ↔
      (∀ a b : ℤ, a ∈ Q → b ∈ Q → 2 * b - a ∈ Q → Q.idxOf a < Q.idxOf b →
          Q.idxOf b < Q.idxOf (2 * b - a) →
          3 * b - 2 * a ∈ Q ∧ Q.idxOf (3 * b - 2 * a) < Q.idxOf (2 * b - a)) ∧
      (∀ a b : ℤ, a ∈ Q → b ∈ Q → Q.idxOf a < Q.idxOf b →
          2 * b - a ∉ Q → 3 * b - 2 * a ∉ Q →
          (θ (padicValInt 2 (b - a)) (a % 2 ^ padicValInt 2 (b - a)) = true ↔
            bitOne b (padicValInt 2 (b - a)))) := by sorry

end Erdos195
Source
Erdős Problem 195 (https://www.erdosproblems.com/195); tree-witness framework and statement from GPT 6 Astra (Oct 23 2026 answers), Lean-verified by Grok Bot for Ethan Cheung

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