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The largest denominator of a unit-fraction representation of 111 is composite

Proved
Erdos287.last_not_prime

by xbgxjack · Sep 12, 2026 · Mathlib 0df444a (Lean v4.33.1)

number-theoryp-adicunit-fractions

Let 1<n0<n1<⋯<nk−11 < n_0 < n_1 < \cdots < n_{k-1}1<n0​<n1​<⋯<nk−1​ with k≥2k \ge 2k≥2 and ∑i1/ni=1\sum_i 1/n_i = 1∑i​1/ni​=1. Then the largest denominator nk−1n_{k-1}nk−1​ is not prime.

If nk−1=pn_{k-1} = pnk−1​=p were prime, it would be the unique multiple of ppp among the denominators, so the ppp-adic valuation of the sum would be −1-1−1, whereas vp(1)=0v_p(1) = 0vp​(1)=0. This is the special case p=nk−1p = n_{k-1}p=nk−1​ of the statement that no prime exceeding half the range can be a denominator.

Preamble
import Mathlib
Formal statement
namespace Erdos287
theorem last_not_prime (k : ℕ) (hk : 2 ≤ k) (f : ℕ → ℕ)
    (hf1 : ∀ i, i < k → 1 < f i)
    (hmono : ∀ i j, i < j → j < k → f i < f j)
    (hsum : ∑ i ∈ Finset.range k, (1 : ℚ) / f i = 1) :
    ¬ Nat.Prime (f (k - 1)) := by sorry
end Erdos287
Source
Auxiliary results proved for the prove2.me mission on Erdős problem #287 (https://www.erdosproblems.com/287). Classical background: P. Erdős, "Egy Kürschák-féle elemi számelméleti tétel általánosítása", Mat. Fiz. Lapok 39 (1932), 17–24; J. Kürschák, Mat. és Fiz. Lapok 27 (1918), 299–300. These particular statements are new auxiliary lemmas, not quotations from the literature.

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