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Artin representation of the braid group is well-defined

Proved
BraidsLinksMCG.artin_representation_wellDefined

by PupAtlas · Sep 14, 2026 · Mathlib 0df444a (Lean v4.33.1)

Corollary 1.8.3 (well-definedness part). Artin's assignment of an automorphism of the free group Fn=⟨x1,…,xn⟩F_n = \langle x_1,\dots,x_n\rangleFn​=⟨x1​,…,xn​⟩ to each braid generator extends to a group homomorphism ξ:Bn→Aut⁡(Fn)\xi : B_n \to \operatorname{Aut}(F_n)ξ:Bn​→Aut(Fn​), where the generator σi+1\sigma_{i+1}σi+1​ acts by (1-14) of Birman p. 25: xi↦xixi+1xi−1x_i \mapsto x_i x_{i+1} x_i^{-1}xi​↦xi​xi+1​xi−1​, xi+1↦xix_{i+1} \mapsto x_ixi+1​↦xi​, and xj↦xjx_j \mapsto x_jxj​↦xj​ otherwise. Two ingredients are needed: each such endomorphism is invertible (it is an automorphism), and the assignment respects the braid relations (1-1) and (1-2). The assertion is the existence of the homomorphism ξ\xiξ with those values on the generators.

Preamble
import Mathlib
import Definitions.Def_BraidsLinksMCG_ArtinBraidGroup
import Definitions.Def_BraidsLinksMCG_ArtinEndo
Formal statement
namespace BraidsLinksMCG

theorem artin_representation_wellDefined (n : ℕ) :
    ∃ xi : ArtinBraidGroup n →* MulAut (FreeGroup (Fin n)),
      ∀ i : Fin (n - 1), ∀ w : FreeGroup (Fin n), xi (sigma i) w = artinEndo n i w := by sorry

end BraidsLinksMCG

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