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Stationarity and complementary slackness extraction

Proved
VectorSpaceOpt.kkt_complementary_slackness

by wenxinzhang · Aug 25, 2026 · Mathlib c5ea003 (Lean v4.30.0)

complementary-slacknessdual-positivekktstationarity

Let a cone-positive continuous functional z₀ accompany a feasible constraint value xConstraint. Suppose the separating inequality

0≤f′h+z0(xConstraint+G′h)0 ≤ f'h + z₀(xConstraint+G'h)0≤f′h+z0​(xConstraint+G′h)

holds for every direction h in the decision space. Then the part linear in h must vanish, and the remaining constant is forced to vanish by feasibility and positivity. Consequently, f' + z₀ ∘ G' = 0 and z₀(xConstraint) = 0. This theorem isolates the sign-sensitive algebra at the end of p. 250. It is a small but valuable reusable interface: geometric separation need only produce the universal affine inequality, after which stationarity and complementary slackness follow without any further topology or differentiability.

Preamble
import Definitions.Def_VectorSpaceOpt_cone_optimization
Formal statement
namespace VectorSpaceOpt

/-- The stationarity and complementary-slackness extraction on p. 250. -/
theorem kkt_complementary_slackness
    {X Z : Type*}
    [NormedAddCommGroup X] [NormedSpace ℝ X]
    [NormedAddCommGroup Z] [NormedSpace ℝ Z]
    (P : ConvexCone ℝ Z) (xConstraint : Z)
    (f' : X →L[ℝ] ℝ) (G' : X →L[ℝ] Z) (z₀ : Z →L[ℝ] ℝ)
    (hz : dualPositive P z₀) (hfeas : coneLE P xConstraint 0)
    (hsep : ∀ h : X, 0 ≤ f' h + z₀ (xConstraint + G' h)) :
    f' + z₀.comp G' = 0 ∧ z₀ xConstraint = 0 := by
  sorry

end VectorSpaceOpt
Source
David G. Luenberger, Optimization by Vector Space Methods (Wiley, 1969), Chapter 9, §9.4, final extraction in the proof of Theorem 1, printed p. 250 (physical PDF p. 268). Scan: https://sites.science.oregonstate.edu/~show/old/142_Luenberger.pdf
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What the Lean code literally says, in plain math · gpt-5

Let X,ZX,ZX,Z be real normed spaces, PPP a convex cone in ZZZ, c∈Zc∈Zc∈Z, f′:X→Rf':X→ℝf′:X→R and G′:X→ZG':X→ZG′:X→Z continuous real-linear maps, and z0:Z→Rz₀:Z→ℝz0​:Z→R a continuous real-linear functional. Assume z0z₀z0​ is nonnegative on PPP, assume c≤P0c≤_{P}0c≤P​0—that is, −c∈P-c∈P−c∈P—and assume that for every h∈Xh∈Xh∈X, 0≤f′h+z0(c+G′h)0≤f'h+z₀(c+G'h)0≤f′h+z0​(c+G′h). Then f′+z0∘G′f'+z₀∘G'f′+z0​∘G′ is the zero functional on XXX and z0(c)=0z₀(c)=0z0​(c)=0. The separator inequality includes h=0h=0h=0 and both arbitrary hhh and its negative; there are no differentiability, completeness, interior, or regularity hypotheses in this theorem.

Human review
  • Endorsed by Shuze Chen · Aug 26, 2026

  • Endorsed by wenxinzhang · Aug 26, 2026

    Confirmed by the mission captain (proposal self-audit).

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