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A crossed-module bispace induces a G-bispace

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QAlgorithms.Papers.Independent.Intakethird100.P93.lemma_2_3

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let t:G→Ht:G\to Ht:G→H be a topological crossed module, with continuous action α:H→Aut⁡(G)\alpha:H\to\operatorname{Aut}(G)α:H→Aut(G). Thus t(α(h)g)=ht(g)h−1t(\alpha(h)g)=ht(g)h^{-1}t(α(h)g)=ht(g)h−1 and α(t(g))k=gkg−1\alpha(t(g))k=gkg^{-1}α(t(g))k=gkg−1. Put G1=ker⁡tG_1=\ker tG1​=kert and give both G/G1G/G_1G/G1​ and H/t(G)H/t(G)H/t(G) their quotient topologies. Assume their quotient projections admit continuous local sections. All actions, structure maps and isomorphisms below are continuous, all principal bundles are locally trivial, and a bispace has a nonempty principal homogeneous underlying right space.

Let (X,ψ)(X,\psi)(X,ψ) be an (H,G)(H,G)(H,G)-bispace with right action denoted by xgxgxg. Define

g⋅x=x α(ψ(x))−1(g).g\cdot x=x\,\alpha(\psi(x))^{-1}(g).g⋅x=xα(ψ(x))−1(g).

This is a continuous left action, its orbit maps are homeomorphisms G→XG\to XG→X, and it commutes with the given right action. Together the two principal actions make XXX a GGG-bispace with structure map α∘ψ\alpha\circ\psiα∘ψ, so xg=α(ψ(x))(g)⋅xxg=\alpha(\psi(x))(g)\cdot xxg=α(ψ(x))(g)⋅x. This constructs the induced bispace rather than assuming its axioms.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P93
Formal statement
namespace QAlgorithms.Papers.Independent.Intakethird100.P93

universe u

variable {G H : Type u} [Group G] [TopologicalSpace G] [IsTopologicalGroup G]
  [Group H] [TopologicalSpace H] [IsTopologicalGroup H]

variable (C : CrossedModule G H)

/-- Lemma 2.3, PDF p.4: formula (2.1) defines commuting principal left and right
actions, with G-bispace structure map alpha∘psi. -/
theorem lemma_2_3 {X : Type u} [TopologicalSpace X] (B : Bispace C X) :
    IsInducedGBispace C B := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P93
Source
On the existence of bibundles, arXiv:1102.4388v2, PDF p. 4, Lemma 2.3
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What the Lean code literally says, in plain math · gpt-6.1-sol

Let G,HG,HG,H be topological groups, and let CCC consist of a continuous homomorphism t:G→Ht:G\to Ht:G→H and a homomorphism α:H→Aut⁡(G)\alpha:H\to\operatorname{Aut}(G)α:H→Aut(G) with continuous evaluation, satisfying t(α(h)(g))=h t(g) h−1t(\alpha(h)(g))=h\,t(g)\,h^{-1}t(α(h)(g))=ht(g)h−1 and α(t(g))(k)=gkg−1\alpha(t(g))(k)=gkg^{-1}α(t(g))(k)=gkg−1. Assume that each quotient map G→G/ker⁡tG\to G/\ker tG→G/kert and H→H/t(G)H\to H/t(G)H→H/t(G) has a continuous right inverse on an open neighborhood of every quotient point. Let XXX be a topological space and BBB consist of a continuous right GGG-action x⋅gx\cdot gx⋅g, with X≠∅X\ne\varnothingX=∅ and g↦x⋅gg\mapsto x\cdot gg↦x⋅g a homeomorphism G→XG\to XG→X for every xxx, together with a continuous map ψ:X→H\psi:X\to Hψ:X→H satisfying ψ(x⋅g)=ψ(x)t(g)\psi(x\cdot g)=\psi(x)t(g)ψ(x⋅g)=ψ(x)t(g). Define g⋆x=x⋅α(ψ(x))−1(g)g\star x=x\cdot\alpha(\psi(x))^{-1}(g)g⋆x=x⋅α(ψ(x))−1(g), where the inverse is the inverse automorphism of GGG. The theorem asserts all of the following simultaneously: XXX is nonempty and every right orbit map is a homeomorphism; the map (g,x)↦g⋆x(g,x)\mapsto g\star x(g,x)↦g⋆x is continuous; 1G⋆x=x1_G\star x=x1G​⋆x=x; (gk)⋆x=g⋆(k⋆x)(gk)\star x=g\star(k\star x)(gk)⋆x=g⋆(k⋆x); for every x∈Xx\in Xx∈X there exists a homeomorphism e:G→Xe:G\to Xe:G→X satisfying e(g)=g⋆xe(g)=g\star xe(g)=g⋆x for every ggg; and, for all g,k∈Gg,k\in Gg,k∈G and x∈Xx\in Xx∈X,

g⋆(x⋅k)=(g⋆x)⋅k,x⋅g=α(ψ(x))(g)⋆x.g\star(x\cdot k)=(g\star x)\cdot k, \qquad x\cdot g=\alpha(\psi(x))(g)\star x.g⋆(x⋅k)=(g⋆x)⋅k,x⋅g=α(ψ(x))(g)⋆x.
Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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