A crossed-module bispace induces a G-bispace
OpenQAlgorithms.Papers.Independent.Intakethird100.P93.lemma_2_3Let be a topological crossed module, with continuous action . Thus and . Put and give both and their quotient topologies. Assume their quotient projections admit continuous local sections. All actions, structure maps and isomorphisms below are continuous, all principal bundles are locally trivial, and a bispace has a nonempty principal homogeneous underlying right space.
Let be an -bispace with right action denoted by . Define
This is a continuous left action, its orbit maps are homeomorphisms , and it commutes with the given right action. Together the two principal actions make a -bispace with structure map , so . This constructs the induced bispace rather than assuming its axioms.
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P93
namespace QAlgorithms.Papers.Independent.Intakethird100.P93
universe u
variable {G H : Type u} [Group G] [TopologicalSpace G] [IsTopologicalGroup G]
[Group H] [TopologicalSpace H] [IsTopologicalGroup H]
variable (C : CrossedModule G H)
/-- Lemma 2.3, PDF p.4: formula (2.1) defines commuting principal left and right
actions, with G-bispace structure map alpha∘psi. -/
theorem lemma_2_3 {X : Type u} [TopologicalSpace X] (B : Bispace C X) :
IsInducedGBispace C B := by sorry
end QAlgorithms.Papers.Independent.Intakethird100.P93
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What the Lean code literally says, in plain math · gpt-6.1-sol
Let be topological groups, and let consist of a continuous homomorphism and a homomorphism with continuous evaluation, satisfying and . Assume that each quotient map and has a continuous right inverse on an open neighborhood of every quotient point. Let be a topological space and consist of a continuous right -action , with and a homeomorphism for every , together with a continuous map satisfying . Define , where the inverse is the inverse automorphism of . The theorem asserts all of the following simultaneously: is nonempty and every right orbit map is a homeomorphism; the map is continuous; ; ; for every there exists a homeomorphism satisfying for every ; and, for all and ,
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.