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Symmetry of the matrix J₀(A − Id)(A + Id)⁻¹ for symplectic A

Proved
ConleyZehnder.symplectic_cayley_isHermitian

by Mazecto · Oct 9, 2026 · Mathlib 0df444a (Lean v4.33.1)

conley-zehnder-indexsymplectic-geometrysymplectic-group

Let J0=(0−IdId0)J_0=\begin{pmatrix}0&-\mathrm{Id}\\ \mathrm{Id}&0\end{pmatrix}J0​=(0Id​−Id0​) and let AAA be a real 2n×2n2n\times 2n2n×2n symplectic matrix, AJ0AT=J0AJ_0A^{T}=J_0AJ0​AT=J0​, such that −1-1−1 is not an eigenvalue of AAA. Then the matrix

N=J0 (A−Id) (A+Id)−1N=J_0\,(A-\mathrm{Id})\,(A+\mathrm{Id})^{-1}N=J0​(A−Id)(A+Id)−1

is symmetric: NT=NN^{T}=NNT=N.

This is the symmetric matrix whose signature computes the Conley–Zehnder index of paths that avoid the eigenvalue −1-1−1 (czIndex_two_mul_eq_neg_signature). The statement supplies the symmetry hypothesis needed to apply that formula and signature_eq_zero_of_hyperbolic.

Formalization note: J₀, IsSymplectic and Mat n come from the definition module ConleyZehnder_Setting. Symmetry is Mathlib's Matrix.IsHermitian over ℝ, which for real matrices is NT=NN^{T}=NNT=N. "No eigenvalue −1-1−1" is (A + 1).det ≠ 0.

Preamble
import Definitions.Def_ConleyZehnder_Setting
Formal statement
namespace ConleyZehnder

/-- If `A` is symplectic and `-1` is not an eigenvalue of `A`, then `J₀ (A - Id) (A + Id)⁻¹` is
symmetric. -/
theorem symplectic_cayley_isHermitian {n : ℕ} (A : Mat n) (hA : IsSymplectic A)
    (hd : (A + 1).det ≠ 0) :
    (J₀ n * (A - 1) * (A + 1)⁻¹).IsHermitian := by sorry

end ConleyZehnder
Source
Gutt, Generalized Conley-Zehnder index, Ann. Fac. Sci. Toulouse Math. 23 (2014) 907-932, https://doi.org/10.5802/afst.1430 (arXiv:1307.7239); Cayley transform of symplectic matrices (standard)

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