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Averaging improvement requires a child better than vertex counting

Proved
Hirsch.weighted_cover_improvement_requires_smaller_child

by jjosh · Sep 10, 2026 · Mathlib c5ea003 (Lean v4.30.0)

face-coverformalizationgraph-diameterpolyhedra

Let VVV be a finite set covered by finite subsets FiF_iFi​ with nonnegative integer weights wiw_iwi​, so every element receives covering weight at least q>0q>0q>0. Let BiB_iBi​ be nonnegative integers. If the averaging certificate

⌊∑iwi(Bi+1)q⌋−1\left\lfloor\frac{\sum_i w_i(B_i+1)}q\right\rfloor-1⌊q∑i​wi​(Bi​+1)​⌋−1

is strictly less than ∣V∣−1|V|-1∣V∣−1, then some positively weighted subset satisfies Bi+1<∣Fi∣B_i+1<|F_i|Bi​+1<∣Fi​∣. Division and subtraction are the natural-number operations. This is a finite counting theorem: it bounds what an averaging certificate can achieve, not an actual polytope diameter. No geometric or graph assumption is implicit.

Preamble
import Mathlib
import Definitions.Def_Hirsch_model
open scoped BigOperators RealInnerProductSpace
open Set Hirsch
set_option autoImplicit false
attribute [local instance] Classical.propDecidable
set_option maxHeartbeats 12000000
Formal statement
namespace Hirsch

theorem weighted_cover_improvement_requires_smaller_child {V ι : Type*} [Fintype V] [Fintype ι] [DecidableEq V]
    (F : ι → Finset V) (B weight : ι → ℕ) (q : ℕ) (hq : 0 < q)
    (hcover : ∀ v, q ≤ ∑ i, if v ∈ F i then weight i else 0)
    (hsmall : (∑ i, weight i * (B i + 1)) / q - 1 < Fintype.card V - 1) :
    ∃ i, 0 < weight i ∧ B i + 1 < (F i).card := by sorry

end Hirsch
Source
https://github.com/jjoshua2/prove2me-work/blob/681314640b6f84792d8ae011c3534a6e8c456930/Solutions/PolynomialFaceCoverBarrier.lean ; declaration HirschFaceCoverBarrier.improving_certificate_requires_improving_child; pinned CI run 34532572816.

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