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Quaternionic Hilbert spaces: composites have fewer than KAKBK_AK_BKA​KB​ degrees of freedom

Proved
HardyFiveAxioms.quaternionic_composite_deficit

by Lucas · Oct 2, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricsmathematical-physicsquantum-foundations

Let KH(N)=N+4(N2)=2N2−NK_{\mathbb H}(N)=N+4\binom N2=2N^2-NKH​(N)=N+4(2N​)=2N2−N be the number of degrees of freedom of quaternionic quantum theory, i.e. signature (1,4,0,… )(1,4,0,\dots)(1,4,0,…). For all NA,NB≥2N_A,N_B\ge2NA​,NB​≥2,

KH(NANB)<KH(NA) KH(NB).K_{\mathbb H}(N_AN_B)<K_{\mathbb H}(N_A)\,K_{\mathbb H}(N_B).KH​(NA​NB​)<KH​(NA​)KH​(NB​).

So quaternionic quantum theory violates K=KAKBK=K_AK_BK=KA​KB​ of Axiom 4.

Formalization Note For NA=1N_A=1NA​=1 or NB=1N_B=1NB​=1 equality holds.

Preamble
import Mathlib
import Definitions.Def_hardy2001_signature
Formal statement
namespace HardyFiveAxioms

/-- Hardy 2001, Section 8.1: for quaternionic Hilbert spaces (signature `(1, 4, 0, …)`), a
composite system has fewer degrees of freedom than the product of those of its subsystems. -/
theorem quaternionic_composite_deficit (NA NB : ℕ) (hA : 2 ≤ NA) (hB : 2 ≤ NB) :
    dofOfSignature [1, 4] (NA * NB) < dofOfSignature [1, 4] NA * dofOfSignature [1, 4] NB := by sorry

end HardyFiveAxioms
Source
L. Hardy, *Quantum Theory From Five Reasonable Axioms*, arXiv:quant-ph/0101012v4 (2001), https://arxiv.org/abs/quant-ph/0101012, p. 17, Section 8.1, paragraph on quaternionic Hilbert spaces
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic)

NON-BLIND READ-BACK — NOT INDEPENDENT TESTIMONY. This read-back was written by the same agent (Aristotle, by Harmonic) that drafted the Lean statement below, with full knowledge of the source paper and of the intended meaning. It was not produced by a blind, independent auditor, so it may share the drafter's blind spots. Reviewers must not treat it as independent confirmation of faithfulness; compare the Lean code against the source directly.

For natural numbers NA≥2N_A\ge2NA​≥2 and NB≥2N_B\ge2NB​≥2, writing K(N)=(N1)+4(N2)K(N)=\binom N1+4\binom N2K(N)=(1N​)+4(2N​) (the signature function for [1,4][1,4][1,4]):

K(NA⋅NB)<K(NA)⋅K(NB),K(N_A\cdot N_B)<K(N_A)\cdot K(N_B),K(NA​⋅NB​)<K(NA​)⋅K(NB​),

a strict inequality of natural numbers.

Human review
  • Endorsed by Shuze Chen · Oct 8, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 8, 2026

    Confirmed by the mission captain (proposal self-audit).

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