Theorem 4.11 — unique weak solution of −Δu = f in H¹₀(Ω) for f ∈ H⁻¹(Ω)
ProvedHunterPDE.Elliptic.dirichlet_existenceLet be an open set in that is bounded in some direction, and let be a bounded linear functional on . Then there is a unique weak solution of in the sense of Definition 4.2, that is,
This is the model existence theorem of the chapter: the weak Dirichlet problem for the Laplacian is well posed.
Formalization Note. is StrongDual ℝ (H10 n Ω), the bounded linear functionals on with its standard norm (Definition 4.1).
import Mathlib import Definitions.Def_HunterPDE_Elliptic_H10 open MeasureTheory
namespace HunterPDE.Elliptic
/-- Theorem 4.11 of Hunter, *Notes on PDEs* (revised 6/18/2014), p. 99: if `Ω` is an open set in
`ℝⁿ` that is bounded in some direction and `f ∈ H⁻¹(Ω)`, then there is a unique weak solution
`u ∈ H¹₀(Ω)` of `−Δu = f` in the sense of Definition 4.2, i.e.
`∫_Ω Du · Dφ dx = ⟨f, φ⟩` for all `φ ∈ H¹₀(Ω)`.
`H⁻¹(Ω)` is the space of bounded linear functionals on `H¹₀(Ω)` with its standard norm
(Definition 4.1), `StrongDual ℝ (H10 n Ω)`. -/
theorem dirichlet_existence {n : ℕ} (Ω : Set (EuclideanSpace ℝ (Fin n))) (hΩ : IsOpen Ω)
(hΩd : BoundedInSomeDirection Ω) (f : StrongDual ℝ (H10 n Ω)) :
∃! u : H10 n Ω, ∀ φ : H10 n Ω, ∫ x in Ω, inner ℝ (grad u x) (grad φ x) = f φ := by sorry
end HunterPDE.Elliptic
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What the Lean code literally says, in plain math · claude-opus-5-5
Let , and let satisfy two hypotheses:
- is open;
- is bounded in some direction: there are a unit vector and reals with on .
is the closure, in , of the span of jets of smooth compactly supported with closed support in . Its norm is , and is the second component of a fixed representative of .
Let be any continuous linear functional , continuous for that norm.
The theorem asserts that there is exactly one such that
Uniqueness is as an element of , that is, of the almost-everywhere class of the pair .
Degenerate cases:
- : the directional-boundedness hypothesis is unsatisfiable, so the statement is vacuous.
- with : and , so is the unique solution.
- Integrability: the integrand is integrable, because and are square-integrable. No default integral value arises.
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.