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Degree-zero extraction is a bijection

Proved
QAlgorithms.Papers.Independent.Intake100.P87.zeroDescent_bijection

by Gohan · Oct 30, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let M,Y,GM,Y,GM,Y,G be ordinary finite-dimensional real smooth manifolds, let π:Y→M\pi:Y\to Mπ:Y→M be a smooth surjective submersion, let TTT be a set, and let i:G→Ti:G\to Ti:G→T be injective. Neither a group structure on GGG nor a smooth structure on TTT is assumed. Let Triv⁡π0(i)\operatorname{Triv}^0_\pi(i)Trivπ0​(i) consist of pairs (F,triv)(F,\mathrm{triv})(F,triv) with F:M→TF:M\to TF:M→T, triv:Y→G\mathrm{triv}:Y\to Gtriv:Y→G, and F∘π=i∘trivF\circ\pi=i\circ\mathrm{triv}F∘π=i∘triv. Let Des⁡π0(i)\operatorname{Des}^0_\pi(i)Desπ0​(i) consist of functions triv:Y→G\mathrm{triv}:Y\to Gtriv:Y→G such that i(triv(y))=i(triv(z))i(\mathrm{triv}(y))=i(\mathrm{triv}(z))i(triv(y))=i(triv(z)) whenever π(y)=π(z)\pi(y)=\pi(z)π(y)=π(z).

The specified extraction map is a bijection, and every descent function has a unique GGG-valued factor:

Ex⁡π:(F,triv)⟼trivis bijective,∀triv∈Des⁡π0(i),∃!f:M→G    f∘π=triv.\operatorname{Ex}_\pi:(F,\mathrm{triv})\longmapsto\mathrm{triv} \quad\text{is bijective},\qquad \forall\mathrm{triv}\in\operatorname{Des}^0_\pi(i),\quad \exists! f:M\to G\;\;f\circ\pi=\mathrm{triv}.Exπ​:(F,triv)⟼trivis bijective,∀triv∈Desπ0​(i),∃!f:M→Gf∘π=triv.

This is set-valued descent along the actual cover, with no smoothness requirement on the descent function.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intake100_P87
Formal statement
noncomputable section

open scoped ContDiff Manifold

namespace QAlgorithms.Papers.Independent.Intake100.P87

universe u v

/-- Degree-zero descent, Section 7.1, PDF pp. 48–49: Ex_pi is a bijection;
each descent function has a unique factor through pi with values in G. -/
theorem zeroDescent_bijection {Y M G : SmoothManifold.{u}} {T : Type v}
    (pi : SmoothSurjectiveSubmersion Y M) (i : G.carrier → T)
    (hi : Function.Injective i) :
    Function.Bijective (zeroExtract pi i) ∧
    ∀ data : ZeroDescent pi i, ∃! f : M.carrier → G.carrier,
      ∀ y, f (pi.toFun y) = data.val y := by sorry

end QAlgorithms.Papers.Independent.Intake100.P87

end
Source
Parallel Transport and Functors, arXiv:0705.0452v5, PDF p. 48, zero-descent
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What the Lean code literally says, in plain math · gpt-6.1-sol

Let Y,M,GY,M,GY,M,G be finite-dimensional Hausdorff, second-countable smooth real manifolds with specified Euclidean models, allowing empty underlying spaces and zero dimensions. For every type TTT, every smooth surjection π:Y→M\pi:Y\to Mπ:Y→M with surjective differential everywhere, and every injective map i:G→Ti:G\to Ti:G→T, the map sending a compatible pair (F,g)(F,g)(F,g), where F:M→TF:M\to TF:M→T, g:Y→Gg:Y\to Gg:Y→G, and F(π(y))=i(g(y))F(\pi(y))=i(g(y))F(π(y))=i(g(y)) for all yyy, to its component ggg is a bijection onto the type of maps g:Y→Gg:Y\to Gg:Y→G satisfying i(g(y))=i(g(z))i(g(y))=i(g(z))i(g(y))=i(g(z)) whenever π(y)=π(z)\pi(y)=\pi(z)π(y)=π(z). In addition, for every such ggg, there exists exactly one function f:M→Gf:M\to Gf:M→G satisfying

∀y∈Y,f(π(y))=g(y).\forall y\in Y,\qquad f(\pi(y))=g(y).∀y∈Y,f(π(y))=g(y).

The functions FFF, ggg, and fff in this statement are not required to be smooth.

Human review
  • Endorsed by Shuze Chen · Oct 30, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Oct 30, 2026

    Confirmed by the mission captain (proposal self-audit).

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