lean_workbook_plus_17974

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Let $a,b,c>0$ . Prove that $2ab+c^2 \ge 2abc(\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{c+a})$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_17974 (a b c : ℝ) (ha : 0 < a) (hb : 0 < b) (hc : 0 < c) : 2 * a * b + c ^ 2 ≥ 2 * a * b * c * (1 / (a + b) + 1 / (b + c) + 1 / (c + a))   :=  by sorry

Source

https://huggingface.co/datasets/internlm/Lean-Workbook

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